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Old February 9th 06, 01:50 PM posted to rec.aviation.student,rec.aviation.piloting
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Default Can a Plane on a Treadmill Take Off?

"Peter Duniho" wrote:

"alexy" wrote in message
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Just to "set the hook" here, are you saying that it will be possible
to have the conveyer move backwards fast enough that the plane remains
still, even under full power, and with no brakes on?


I thought you had already established that it would be possible, and that
the treadmill speed is "somewhat below the speed of light"? You didn't
appear to solve the "materials integrity" aspect of the problem, but that
seems like a minor quibble.

You know, there is a fallacy in my reasoning that I am surprised no
one has called me on. We are used to aerodynamic drag, which increases
as the square of velocity. But if my memory of high school physics is
correct (and if Newton hasn't changed his mind in the last 40
yearsg) the friction between two bodies is a coefficient of friction
times the force normal to the motion (i.e., the weight of the plane).
No component for the relative velocities of the two bodies! So the
drag due to wheels is small, and speeding up the conveyer will not
increase that small drag, at least until you get to the "noise"
elements that make the idealized drag model imperfect.

I guess that by _accelerating_ the conveyer, you could make the plane
use all of its power for a short while providing the angular
acceleration to the wheels, but you very quickly get to relativistic
speeds, without ever reaching a steady state tradeoff for the
engine/prop's thrust.

Much easier to just read the problem as stated, and have the conveyer
only move as fast backwards as the plane moves forward!!

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