I need to retreat a little here. The formula I gave looks to be a
curve fit to an empirical data set, and that data may have been
obtained with evaporative losses as a factor. I seem to remember,
however, the experiments were done observing heat loss from plastic
bottles filled with water, the thickness of the plastic offering more
or less the same thermal impedence as does skin.

So, I hereby extinguish the implied flame.

Sorry about that. Now I'm off to slay more meaningful dragons and save
a maiden or two.

CLEAR!



imperical data ting formay be wrong On Feb 22, 2:20 am, "Tony"
wrote:
I don't think so.

The windchill temperature is calculated using the following formula:

Windchill (ºF) = 35.74 + 0.6215T - 35.75(V^0.16) + 0.4275T(V^0.16)

Whe T = Air Temperature (F)
V = Wind Speed (mph)
^ = raised to a power (exponential)

Windchill Temperature is only defined for temperatures at or below 50
degrees F and wind speeds above 3 mph. Bright sunshine may increase
the windchill temperature by 10 to 18 degrees F.

On Feb 22, 2:12 am, Alan Gerber wrote:



In rec.aviation.piloting Tony wrote:

Fans in your computer are there to move air mass against hot objects
to carry the heat away, they are trying to create 'wind chill' inside
the computer. You can google 'convective heat loss' or 'forced air
cooling' if you want to explore the subject in more depth.

That's not what wind chill is about. You need to take into account
evaporative cooling, which has a significant effect.

... Alan
--
Alan Gerber
PP-ASEL
gerber AT panix DOT com- Hide quoted text -

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