In rec.aviation.piloting Matt Whiting wrote:
wrote:
The coefficient of drag for motorcycles is usually pretty bad unless
they are faired, and it still ain't great.
Yes.
The power required to overcome drag is 1/2(p*v^3*A*C)
No. It is v^2 unless they have changed the physics since I was an aero
engineering student back in the 70s.
Yes.
The drag goes up with the square of velocity, the POWER required to
overcome the drag goes up as the cube.
Force: Fd = 1/2(p*v^2*A*C)
Power: Pd = Fd * v = 1/2(p*v^3*A*C)
--
Jim Pennino
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