"Tina" wrote in message
...
You are in error again.

- The calculation would be based on a triangle, one length is earth
- radius, the other, earth radius plus tower height. The third length is
- the geometric distance from tower top to earth horizon.
-
- Oh, be sure to square (that means multiply it by itself) the two known
- lengths, subtract one (earth radius squared) from the other (earth
- radius plus tower heigth squared), and extract the sqare root.
-
- Be sure to use consistant units: you do know there are 5280 feet in a
- mile, don't you?
-
- What part don't YOU understand?

He's switched now to an argument about the limits of resolution of the eye. He's still
full of crap, but what else is new?.


On Jan 3, 5:57 pm, Mxsmanic wrote:
Tina writes:
The question not answered, assuming both a spherical cow and a round
smooth earth with no atmosphere, is how you, using right triangles,
know the distance to the horizon.

I've given an explanation. What part don't you understand?