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Old October 6th 06, 05:29 AM posted to rec.aviation.homebuilt
-=chewy=-
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Default Increase efficiency of rotating shaft.

Canalbuilder wrote:
This comes from a failure to understand the forces involved. Assuming
that it is equilibrium the load from the weighted plate will be
transferred to the pulleys at right angles to the plane of contact. This
plane of contact will be the circumference of the pulley, and any force
at right angles to it will pass through the pulley centres and no moment
(torque) will be generated.


"Pulleys are designed so that from points a and a` to points b and b`,
radii of pulleys continuously decrease."

The "Case 2" pulleys are like cam lobes, and the plane of contact isn't
perpendicular to the radius. But, as Ron says, Jigar ignores energy
needed to raise the plate.