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#31
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Er, I'm only a humble Nimbus 4 pilot (not an instructor),
so what do I know about things? 'I also understand that Nimbus 4s have a non-standard spin recovery procedure, which further complicates the issue. ' Derek, my Nimbus 4 flight manual says: 'a) Apply opposite rudder. b) Hold ailerons neutral. c) Ease control sick forward until roation ceases and the airflow is restored. d) Centralise rudder and pull gently out of the dive. Recovery speeds are between 70 - 113 knots - depending on the flap setting. If necessary, flaps must therefore be reset at '0' or '-1' so as to avoid exceeding their speed limits.' Sounds to me very similar to what Mr Piggott taught me all those years ago? At 17:54 12 July 2005, Derek Copeland wrote: Bert Willing wrote on 12th July. You're point number two doesn't hold: At constant speed (whichever speed), a wing of a sailplane will never produce more lift than corresponds to the weight of the glider. Otherwise you would be climbing. Your main original point is absolutely right. -------------------------------------------------------------- Er, I'm only a humble gliding instructor, so what do I know about things? You are also right in that in steady flight lift must equal the weight of the glider. However in a spiral dive you are in accelerated flight and the glider could effectively weigh several times its own weight, and the wings (if not stalled) have to produce the equivalent extra amount of lift to balance this. If you are pulling more than 3.5 g at high speeds, opening the airbrakes could just be enough to finish things off, due to the extra bending load on the wings this entails. The correct recovery from a spiral dive is just to carefully reduce the angle of bank while keeping the stick fairly well back, by the way. As an instructor I do lots of spins and spiral dives, so can easily recognise what is going on. Many good cross-country pilots haven't done either for years, so could be caught out should either occur unexpectedly . The recovery actions are quite different. I also understand that Nimbus 4s have a non-standard spin recovery procedure, which further complicates the issue. Derek Copeland ================================================= ================= ========== Any opinions expressed in this e-mail are those of the individual and not necessarily those of ADT Fire and Security. Any prices for the supply of goods or services are only valid if supported by a formal written quotation. This e-mail and any files transmitted with it, including replies and forwarded copies (which may contain alterations) subsequently transmitted from ADT Fire and Security are confidential and solely for the use of the intended recipient. If you are not the intended recipient or the person responsible for delivery to the intended recipient, be advised that you have received this e-mail in error and that any use is strictly prohibited. In this event, please notify us via e-mail at ' or telephone on 0121 255 6499 and then delete the e-mail and any copies of it. WebSite: www.adt-fire-and-security.co.uk ================================================= ================= ========== -- |
#32
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Just for general clarification, Section 4.5.6 of my
Nimbus 4T flight manual says: “Note: In order to achieve a high maneuverability, a favourable c/g position (when using the fin tank) and a maximum in ground clearance of the wing tips on take-off and landing, it is always recommended to fill the inboard water tanks first.” I know it is the opposite for the Nimbus 3, I assume the wings are just that much stronger on the 4. In my experience it does make take off less fraught and handling a bit nicer on the 4 than the 3. Mike At 18:30 11 July 2005, Roy Bourgeois wrote: I think what Bert says is technically correct (wing load doesn't change when you open the air brakes) - but the distribution does change a lot - especially on a ship like the N3 & N4 where the brakes are located inboard on the inner panels. Stated differently, when the brakes are opened the outer panels are being asked to do more work supporting the fuselage (and non flying portions or the inner panels) than before the dive brakes were opened. The Nimbus 3 and 4 are placarded against carrying water ballast in the inner panel tanks with the outer panel tanks empty for structural reasons. You also must dump the inner tanks first. The same structural problem occurs when the dive brakes are open and that part of the inner panel becomes 'dead weight'. So - while the brakes should be used to prevent the glider getting to extreme speeds - we need to be cautious about suggesting that nothing bad is going to happen if you open them at extreme speeds. Roy B. (Nimbus 3 # 65) |
#33
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Michael Clarke wrote:
Derek, my Nimbus 4 flight manual says: a) Apply opposite rudder. b) Hold ailerons neutral. c) Ease control sick forward until roation ceases and the airflow is restored. d) Centralise rudder and pull gently out of the dive. No surprize: JAR22 explicitely demands "standard spin recovery". And it must demonstrated from a spin of "at least 5 turns" and with "the most unfavorable configuration". (Cited from memory, so the exact wording may be different.) Stefan |
#34
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At 20:18 13 July 2005, T O D D P A T T I S T wrote:
Don Johnstone wrote: If you have to open the brakes, do so before Vne is reached Absolutely correct, carve that in stone. The implication here is that if you find yourself extremely nose down, but at an initially low speed, opening the brakes is a desirable action. I disagree. Opening the brakes might be advisable if brakes were able to produce large amounts of drag - sufficient to limit you to speeds below Vne - but that is generally not true. So, your only other option is to get the nose back up to stop the acceleration. The only way to do that is to apply the maximum force possible in a direction perpendicular to the downwardly angled path of the aircraft to curve it back towards level. A force perpendicular to the path of the aircraft is called 'lift' and by opening the brakes you prevent much of the wing from producing the lift you desperately need to bring you back to level flight. This delays the critical recovery. Up until you reach Va, you can operate the wings at maximum lift coefficient and produce maximum lift without risk of structural damage, and that's exactly what you want to do to get the nose back up. In addition, by opening the brakes, you seriously increase the risk that the pilot will overstress the aircraft at higher speeds. With brakes open, the max G load for many gliders is so low that the pilot simply does not think he's about to break anything. His built in warning system does not begin to go off until much higher G loads are felt. Finally, if you open the brakes, you increase the altitude loss significantly, a potentially critical factor in a low altitude recovery. The proposal to use a tail chute does not suffer from these problems, as a tail chute does not decrease lift or max G limits. It also has the advantage of allowing recovery from otherwise unrecoverable spin modes. I accept what you say my original reponse was to the whole paragraph 'My main original point was that the first action in any sort of loss of control situation in a flapped glider must be to select neutral or negative flap. If you have to open the brakes, do so before Vne is reached' I standby that. It is important to select a non positive flap setting and if the brakes are going to be used it should be before VNE is reached. |
#35
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T o d d P a t t i s t a écrit :
The implication here is that if you find yourself extremely nose down, but at an initially low speed, opening the brakes is a desirable action. I disagree. A force perpendicular to the path of the aircraft is called "lift" and by opening the brakes you prevent much of the wing from producing the lift you desperately need to bring you back to level flight. This delays the critical recovery. No. The radius of curvature of your recovery trajectory is proportionnal to lift, but inversly proportionnal to the square of speed. Thus, even with less lift, the radius may be smaller with airbrakes out. Finally, if you open the brakes, you increase the altitude loss significantly, a potentially critical factor in a low altitude recovery. No. Smaller radius means smaller altitude loss (though smaller speed means less altitude gain after the low point, but this is not likely to be a problem) -- Denis R. Parce que ça rompt le cours normal de la conversation !!! Q. Pourquoi ne faut-il pas répondre au-dessus de la question ? |
#36
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On Mon, 15 Aug 2005 10:15:22 -0400, T o d d P a t t i s t wrote:
are trying to decide what to do at the point when brakes are closed and speed is fixed at some speed V1. If pilot 1 leaves the brakes closed and pulls to max G for brakes closed, and pilot 2 opens the brakes and pulls to max G for brakes open, pilot 1 will have a smaller radius of curvature, since both are at speed V1. If you are in a situation (perhaps recovering from a spin) with your nose pointing 60 deg down below the horizontal and the ASI reading 180 km/h and accelerating rapidly. You could try: - Pull full airbrakes, and raise the nose by 15 degrees keeping the G force below 2G. In this new attitude (45 degrees nose down) many gliders airbrakes will be speed limiting below VNE. The acceleration will stop and you can pull out of the dive being careful to limit the G force to 2G. - Or, you could leave the dive brakes closed, and attempt to raise the nose by 55 degrees to 5 degrees below the horizon without pulling more than 4G. I have not worked out the maths of the two options but I think that in a clean glass ship, you would have a better chanced completing the first manoeuvre without exceeding VNE than the second. Ian |
#37
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In article ,
Ian wrote: On Mon, 15 Aug 2005 10:15:22 -0400, T o d d P a t t i s t wrote: are trying to decide what to do at the point when brakes are closed and speed is fixed at some speed V1. If pilot 1 leaves the brakes closed and pulls to max G for brakes closed, and pilot 2 opens the brakes and pulls to max G for brakes open, pilot 1 will have a smaller radius of curvature, since both are at speed V1. If you are in a situation (perhaps recovering from a spin) with your nose pointing 60 deg down below the horizontal and the ASI reading 180 km/h and accelerating rapidly. You could try: - Pull full airbrakes, and raise the nose by 15 degrees keeping the G force below 2G. In this new attitude (45 degrees nose down) many gliders airbrakes will be speed limiting below VNE. The acceleration will stop and you can pull out of the dive being careful to limit the G force to 2G. - Or, you could leave the dive brakes closed, and attempt to raise the nose by 55 degrees to 5 degrees below the horizon without pulling more than 4G. I have not worked out the maths of the two options but I think that in a clean glass ship, you would have a better chanced completing the first manoeuvre without exceeding VNE than the second. Another option is to raise the nose 15 degrees with the airbrakes closed, keeping below 4G, and *then* pull the airbrakes. -- Bruce | 41.1670S | \ spoken | -+- Hoult | 174.8263E | /\ here. | ----------O---------- |
#38
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Ian wrote:
If you are in a situation (perhaps recovering from a spin) with your nose pointing 60 deg down below the horizontal and the ASI reading 180 km/h and accelerating rapidly. You could try: [ leave A/B closed and pull 4G ...] I have not worked out the maths of the two options but I think that in a clean glass ship, you would have a better chanced completing the first manoeuvre without exceeding VNE than the second. I couldn't resist the temptation and did the maths. I kind of lost the habit, so it took me 20 minutes. The result is: My intuition was right: Do *not* use the airbrakes. Even in an ideal ship (zero drag) and with the nose pointing vertically down initially, the peak speed is only 240km/h under your assumptions (4g pull-up and 180km/h initially). In a real ship and with only 60 degrees down, the peak speed would of course be lower. Here's the script with the phugoid equation (Mathematica). Feel free to modify the initial conditions and parameters and play around. The unknowns are v1, v2, the horizontal and vertical component of the speed vector. kmh = 1 / 3.6 Ng = 4 g = 9.81 v0 = 180 kmh tmax = 8 dt = .1 v = NDSolve[ { v1'[ t ] == Ng g * v2[ t ] / Sqrt[ v1[ t ]^2 + v2[ t ]^2 ] , v2'[ t ] == Ng g * -v1[ t ] / Sqrt[ v1[ t ]^2 + v2[ t ]^2 ] - g , v1[ 0 ] == 0 , v2[ 0 ] == -v0 } , { v1 , v2 } , { t , 0 , tmax } ][[ 1 ]] Table[ ( Sqrt[ v1[ t ]^2 + v2[ t ]^2 ] /. v ) / kmh , { t , 0 , tmax , dt } ] Regards -Gerhard -- o o Gerhard Wesp | http://www.cosy.sbg.ac.at/~gwesp/ \_/ See homepage for email address! |
#39
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At 04:48 16 August 2005, Gerhard Wesp wrote:
Ian wrote: If you are in a situation (perhaps recovering from a spin) with your nose pointing 60 deg down below the horizontal and the ASI reading 180 km/h and accelerating rapidly. You could try: [ leave A/B closed and pull 4G ...] I have not worked out the maths of the two options but I think that in a clean glass ship, you would have a better chanced completing the first manoeuvre without exceeding VNE than the second. I couldn't resist the temptation and did the maths. I kind of lost the habit, so it took me 20 minutes. The result is: My intuition was right: Do *not* use the airbrakes. Even in an ideal ship (zero drag) and with the nose pointing vertically down initially, the peak speed is only 240km/h under your assumptions (4g pull-up and 180km/h initially). In a real ship and with only 60 degrees down, the peak speed would of course be lower. Here's the script with the phugoid equation (Mathematica). Feel free to modify the initial conditions and parameters and play around. The unknowns are v1, v2, the horizontal and vertical component of the speed vector. kmh = 1 / 3.6 Ng = 4 g = 9.81 v0 = 180 kmh tmax = 8 dt = .1 v = NDSolve[ { v1'[ t ] == Ng g * v2[ t ] / Sqrt[ v1[ t ]^2 + v2[ t ]^2 ] , v2'[ t ] == Ng g * -v1[ t ] / Sqrt[ v1[ t ]^2 + v2[ t ]^2 ] - g , v1[ 0 ] == 0 , v2[ 0 ] == -v0 } , { v1 , v2 } , { t , 0 , tmax } ][[ 1 ]] Table[ ( Sqrt[ v1[ t ]^2 + v2[ t ]^2 ] /. v ) / kmh , { t , 0 , tmax , dt } ] Regards -Gerhard I think the ground might get in the way before I have done the sums :-) |
#40
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T o d d P a t t i s t a écrit :
Last, I'm relying on my recollection of the physics of a pull-out which I calculated long ago. It's not peer reviewed work, and I'm quite far from infallible :-) If I get some time, I'll pull out my old notes. I'd love to have someone put this into Mathematica and verify my recollection of the results. I have no calculation neither, and it would be great to help us compare our guesses... What we need to do so is knowing the airbrakes drag. At 1 g it limits speed to VNE at 30° dive angle, which means that if you get twice this drag at 4 g, even at 90° dive angle the speed will be kept under VNE. Which is not unlikely, since induced drag increase due to airbrakes is high, but once again I have no precise figure yet to prove it. If someone has, please give it... -- Denis R. Parce que ça rompt le cours normal de la conversation !!! Q. Pourquoi ne faut-il pas répondre au-dessus de la question ? |
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