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Sriram Narayan wrote:
That still wouldn't help since the pressure change for a 1000ft change in altitude at 18k would be smaller than at sea level. It would have to have some non-linear spring compensation as a function of absolute pressure. Yes but the non-linearity is very weak. I coded up the formula for the US standard atmosphere (described below) and plotted it. See http://www.burningserver.net/rosinsk...atmosphere.jpg Perhaps the non-linearity is so weak that altimeters neglect it? I don't know. The formula for US standard atmosphere can be derived from the ideal gas approximation (p = rho*R*T) and the hydrostatic approximation (dp/dz = -rho*g). The final equation is: z = T0/gamma * (1 - (p/p0)**(R*gamma/g))) where R=287, T0 = 288K, p0 = 1013.25 mb = 29.92 in, gamma = 6.5 deg/km, g = 9.8. The formula assumes that temperature decreases linearly with altitude, an assumption which becomes invalid above the tropopause. The equation and its derivation can be found in Wallace & Hobbs, "Atmospheric Science", pg. 60-61. Jim Rosinski |
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