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Well, after asking the question, I found most of what I wanted. Just a
matter of putting the right words into a search engine. For those who care, see an excellent report at http://www.grc.nasa.gov/WWW/K-12/airplane/cyl.html The formulas for lift of a cylinder is specified. An example is given that has a 20 foot long cylinder of 2 feet diameter. At 100 mph, 236 rpm rotation of the cylinder yields 1085 lb lift. That seems to answer the question, since the energy required to rotate a 2 foot diameter cylinder which is 20 feet long would be substantial. And, this would not provide any forward motion - just lift. Much easier to use a simple, less complicated wing. But, it might be possible to build something that actually flew. Now I am a bit smarter. Colin N12HS --- Outgoing mail is certified Virus Free. Checked by AVG anti-virus system (http://www.grisoft.com). Version: 6.0.775 / Virus Database: 522 - Release Date: 10/8/04 |
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