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#10
June 20th 06, 02:04 PM
posted to rec.aviation.ifr,rec.aviation.piloting,rec.aviation.student
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NTSB report - ILS and ATC. How does it all come together?
Steven P. McNicoll wrote:
"Mike" wrote in message . .. Using trigonometry, I get ~ 785ft 2.5 miles out from the touch down zone, so your method is pretty accurate. Here's my calculation: Assuming: Distance = 15,000 ft Slope: 3 degrees Height = Distance * sin(Slope) = 785.04 ft. A 3 degree glidepath descends 318 feet per nautical mile. 318 x 2.5 = 795. Sorry, the original calculation was based on bad data. 15,000 feet is not 2.5nm as stated in the original post. 1nm = 6,076ft 2.5nm = 15,190ft Elevation = 15,190 * sin(3-degrees) = 795 ft -- Mike 
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