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![]() "Chad Speer" wrote in message ups.com... Okay, I know I've seen a lot of engineers and technical folks on here. I have a complex math problem relating to the classic wind triangle that I posted on sci.math and received little response. I don't know if they're stumped or just not interested. :-) Here is a copy of my original post and the only useful response I received. Anyone have a solution? (For the controllers here, this is an enhancement we are trying to add to the Falcon program that centers will see next year, which was developed by a controller here at ZKC.) Chad Speer PP-ASEL, IA ATCS, Kansas City ARTCC ************************************************** * ************************************************** * My original post: ***** I am helping someone with a program that estimates wind speed and direction using radar data from aircraft. I need help finding a formula that can determine the wind speed and direction when given the following information for multiple aircraft: direction of travel speed across the ground speed through the air The direction of travel and the speed across the ground are taken from the radar data. The speed through the air is taken from the pilot's flight plan. We're air traffic controllers trying to improve our training tools, so we get access to all the goodies. I know that with information from just one aircraft, the possibilities are endless for the wind speed and direction. I think it is possible to use the same data from two or more aircraft to determine the wind speed and direction. I thought I could come up with a formula to solve this, but the need to reference everything to north in order to achieve actual directions instead of just angles took it way above my head. snip Chad if you know HDG ( ie where you are pointing), GS and TAS then there is only 1 possibility for the wind speed and direction. these can be calculated from the cosine rule. If you know the cosine rule and the sine rule for triangles you can calculate a lot of things. to apply both of these rules draw yourself a little triangle and mark the sides small a,b and c. then mark the angles capital A,B and C where angle A is opposite side a and angle B is opposite side b. cosine rule a^2 = b^2 +c^2 - 2bc cos( A) sine rule a/sin A = b/sin B = c /sin C in the case of the NAV triangle WS= SQRT( GS^2+TAS^2 =2*GS*TAS*cos(HDG-TR)) where WS= windspeed GS = ground speed TAS = airspeed HDG = heading(where you are pointing) TR = track ( where you are going) If you want I can email you an excel spreadsheet that has this already coded. you just enter your TAS, GS and HDG and it will give you the WS and Wind direction. Terry PPL |
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