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On May 10, 3:20 pm, Matt Whiting wrote:
Paul Tomblin wrote: In a previous article, Erik said: Sheista wrote: http://www.thepollspace.com/polls.php?pollid=1359 ![]() I know this already, but it always amazes me to see the wing holding up the plane. It's propped off of the ground on the one wing. I know this happens in the air, it's just neat to see how strong the wings actually are. In the air, the load is distributed along the length of the wing, rather than just on the wing tip. So this wing is taking more torque than a wing in the air. Only if you consider an air load of 1G. I'd have to do that calculation to be sure, but I'm fairly confident that 4G in the air is more moment at the wing root than is 1G at the tip. Matt- Hide quoted text - - Show quoted text - I'm not sure how actual aircraft engineers do it but when I got my engineering degree that isn't how we would do it. Looking at the moment at the root seems to imply that the entire length of the wing is of equal strength and the forces are focused on the root. In fact the wing is not designed to be equal strength throughout, each section of the wing is only as strong as it needs to be. Therefore, the chance of failure (at least ideally) is about equal anywhere along the wing (root, mid section, tip, etc). There may be practical frabrication reasons why you would have one section of a wing "over engineered", but in general, that would not be an engineer's goal. When I was an engineering student we would look at each spar's forces as a continous function using calc. That way we could use dx to see the force on any infinite small section of each spar. Looking at the max force at any dx we could reduce weight (i.e. strength) if one section was stronger than necessary. The strength at that section would be designed to meet the requirement of the force expected. I.e. we wouldn't make the entire wing the same strength if the forces were not the same throughout. -Robert |
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