Standard rate turn in Boeing 757?

From Aerodynamics for Naval Aviators

n=1/cos(bank angle)

n= load factor in G's

ROT=(1,091*tan(bank angle))/V
r= v^2/(11.26*tan (bank angle)

ROT= rate of turn in degrees per second
r= turn radius in feet, divide by 6078 ft/nm to get nm.
V= velocity, knots

At 250 knots and a 30 degree bank this would be a 2.51 degree per second
turn. It would take 107 seconds to make a 270 turn.

John Bell
www.cockpitgps.com

"Garyurbach" wrote in message
...
You got it.

I am a former student pilot (lost interest after moving constantly set me
back), and I need help from someone with ATP experience on this one.

Surely a 757 can make a descending turn 270 degrees in 2.5 minutes? Maybe,
it's
not what an ATP would do to passengers, but it's not some plane-stressing
move?

The move, before the crash, sounded like a spiraling descent, or an
emergency
descent.

Any help would be appreciated, even if it's to point me to someone who can
give
me the answers.

:-)

"John Bell" wrote
From Aerodynamics for Naval Aviators

n=1/cos(bank angle)

n= load factor in G's

True...for a level turn, but when no attempt is made to maintain
altitude, bank angle and load factor are not related.

Bob Moore
Who also preaches from the "bible" :-)

Although John Bell correctly provides the technical calcs to figure the
angle of bank for standard rate turns, the point is the radius [and
ultimately, the rate] of the turn is based on the airspeed, not the size of
the aircraft. If an airplane needs to tighten the turn radius without
increasing the bank angle, it can be done by decreasing speed and/or
descending.