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![]() Harry Andreas wrote: In article , nafod40 wrote: niceguy wrote: What idiot would attempt to divide by zero? God. That's how we get black holes. I'd like to see that equation. I think its not to hard to derive. If gravity is so high that escape velocity (eg for a missile) excedes the speed of light you get it. The fitgerald-lorentz contraction equations. http://en.wikipedia.org/wiki/FitzGer...tz_Contraction Square root of (1-(v^2/C^2)) produces infinit contraction at this speed. I.E. light can't escape and objects have zero lenght and infinite mass. |
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On Fri, 3 Jun 2005 19:21:58 -0700, Eunometic wrote
(in article .com): I think its not to hard to derive. If gravity is so high that escape velocity (eg for a missile) excedes the speed of light you get it. The fitgerald-lorentz contraction equations. http://en.wikipedia.org/wiki/FitzGer...tz_Contraction It isn't the black hole solution that gives the error. The radius of the event horizon (the place where the speed of light equals escape velocity) is the same when calculated classically or with Einstein's gravitation. The problem comes with the singularity, or what happens after that. You get the equivalent to a division by zero in the center, like with anything where you divide by a radius and you try to see what happens at the center. Radius is zero -- oops, condition red -- global causality error! The universe does not allow division by zero. Perhaps it falls in the realm of the absolute elsewhere, or perhaps not. Nobody knows. -- Charlie Springer |
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