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  #31  
Old May 20th 07, 01:05 AM posted to rec.aviation.piloting
Bertie the Bunyip[_2_]
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Mxsmanic wrote in
:

Maxwell writes:

Clueless as usual.


A zero-G parabola is a ballistic trajectory;


No, it isn't.


bertie
  #32  
Old May 20th 07, 01:10 AM posted to rec.aviation.piloting
Mxsmanic
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mike regish writes:

You're accelerating downward at exactly 1 g, or 32 feet per second per
second.


Yes: -1.0 G.

Zero g is zero g.


You're not actually at zero G. You're in free fall, accelerating with the
aircraft at exactly -1.0 G, which negates the acceleration due to gravity.

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  #33  
Old May 20th 07, 01:25 AM posted to rec.aviation.piloting
Bertie the Bunyip[_2_]
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Default Zero G profile

Mxsmanic wrote in
:

mike regish writes:

You're accelerating downward at exactly 1 g, or 32 feet per second
per second.


Yes: -1.0 G.

Zero g is zero g.


You're not actually at zero G. You're in free fall, accelerating with
the aircraft at exactly -1.0 G, which negates the acceleration due to
gravity.


You're a moron.


Bertie
  #34  
Old May 20th 07, 02:19 AM posted to rec.aviation.piloting
Mxsmanic
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Posts: 9,169
Default Zero G profile

Bertie the Bunyip writes:

No, it isn't.


A ballistic trajectory in a vacuum above the Earth's surface and subject only
to gravity.

A more precise but abstract description of the path is an orbital trajectory.

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  #35  
Old May 20th 07, 02:35 AM posted to rec.aviation.piloting
[email protected]
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Posts: 2,892
Default Zero G profile

Mxsmanic wrote:
mike regish writes:


You're accelerating downward at exactly 1 g, or 32 feet per second per
second.


Yes: -1.0 G.


Zero g is zero g.


You're not actually at zero G. You're in free fall, accelerating with the
aircraft at exactly -1.0 G, which negates the acceleration due to gravity.


Velocity and acceleration are vectors and the sign depends on the
coordinate system you define.

Since you didn't define a coordinate system your use of negative
numbers is just a pile of steaming crap designed to produce an
endless arguement since you know most people would just use the
absolute values when diving towards the Earth as the direction is
understood by everyone not designing their responses to start an
endless ****ing contest to show how smart they are.

If you are accelerlating at 1 G in the direction of the Earth, you
experience a force of 0 G.

If you are accelerlating at -1 G in the direction of the Earth, you
experience a force of 2 G.

If you are accelerlating at 1 G in the direction away from Earth, you
experience a force of 2 G.

If you are accelerlating at -1 G in the direction away from Earth, you
experience a force of 0 G.

Twit.

--
Jim Pennino

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  #36  
Old May 20th 07, 04:43 PM posted to rec.aviation.piloting
Bertie the Bunyip[_2_]
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Posts: 896
Default Zero G profile

Mxsmanic wrote in
:

Bertie the Bunyip writes:

No, it isn't.


A ballistic trajectory in a vacuum above the Earth's surface and
subject only to gravity.

A more precise but abstract description of the path is an orbital
trajectory.



Oops, you're wrong again!
Don't you ever get tired of that?


Bertie
 




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