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Ram air
"Maxwell" luv2^fly99@cox.^net wrote in news:jTR0k.192$js1.25
@newsfe24.lga: "Bertie the Bunyip" wrote in message ... "Maxwell" luv2^fly99@cox.^net wrote in : "Bertie the Bunyip" wrote in message ... Didn't know any production aircraft had that. Well, to some extent almost every lightplane does . that's why the carb air intake faces forwards in most of them.Everything is a balancing act with an airplane. More air = more drag. You could try putting a couple of woks with tubes out the back to boost your MP, but you're going to pay for it. !Moooney must have spotted an area of the cowl that would not penalise you in this way and decided to utilise it. Really clever homebuilders do a lot of this kind of stuff as well as, and probably more more importantly, dealing with cooling drag. Have you put the other speed mods on your airplane? I think there's nearly ten knots available in seals and various other tidy it up fairings. Bertie Dumb ass. Its because the size of the scoop increases volume (not pressure), and you already have too much. Nope. Bertie How would you know, dumb ass? I know everything, obviously. Bertie |
#2
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Ram air
On Jun 1, 3:35 am, Tina wrote:
The Mooney 201 has a ram air port, a half a foot under the prop spinner. The POH tells us it can be opened at altitude for a very modest increase in MP and we find maybe a half inch increase in pressure. The idea of the thing is, if the port is looking right at the air being thrust toward it by the prop (it can't be more than 6 inches or so behind it) as well as the air impact from the airplane's motion the air being 'rammed' into it should effectively lower the altitude the engine thinks it's at. Well, a half inch of Hg is about 500 feet or so. The question is, though, wouldn't you think there would be a way to capture a great deal more of the ram air effect and really boost the engine performance? Who wouldn't like to fly at 24 square at 12000 feet without a turbo charger? What makes me wonder about it is, even at 60 mph holding your hand out of the window of a car subjects it to a significant backward pressure, so the energy must be there. Good thinking, but physics prevails. For example we just built a building with sides 10'x20', http://www.flickr.com/photos/dynamics/ and the load computation of a wind at 60 mph is 1 ton on a 200 sq ft surface, being a shear force on the foundation, which is 10#/sq ft. That might sound like alot but in terms of pressure per sq. inch it's, Per sq. inch, divide 10# by 144 = lbs/ sq. inch, ~ .07# / sq. inch. By comparision, sea level pressure is 15#/sq.inch, which is convertible to Hg units. Ramming air increases pressure with speed squared so at 120 mph, pressure is 40#/sq. ft etc. So at 420 mph, ram pressure is up to 3.5 #/sq in. which is about a low as is practical, as in a V-1 buzz bomb. Cheers Ken |
#3
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Ram air
The induction port for the ram air on the m20J bypasses the air filter
as well, so we typically observe about a half inch improvement in MP. That's in line with some of the other numbers offered here. I guess there's no free lunch. There is no way we want to have an IO540 pull the airplane along, nor do we want the fuss with turbo charging. The payback for our typical for real flight mission is just not there. My thought was and is that if it was something pretty obvious someone would have done it on a homebuilt. Actually, knowing some of those guys, it does not have to be obvious at all, they are really creative designers. I had better stick with my day job. with some On Jun 1, 12:28 pm, "Ken S. Tucker" wrote: On Jun 1, 3:35 am, Tina wrote: The Mooney 201 has a ram air port, a half a foot under the prop spinner. The POH tells us it can be opened at altitude for a very modest increase in MP and we find maybe a half inch increase in pressure. The idea of the thing is, if the port is looking right at the air being thrust toward it by the prop (it can't be more than 6 inches or so behind it) as well as the air impact from the airplane's motion the air being 'rammed' into it should effectively lower the altitude the engine thinks it's at. Well, a half inch of Hg is about 500 feet or so. The question is, though, wouldn't you think there would be a way to capture a great deal more of the ram air effect and really boost the engine performance? Who wouldn't like to fly at 24 square at 12000 feet without a turbo charger? What makes me wonder about it is, even at 60 mph holding your hand out of the window of a car subjects it to a significant backward pressure, so the energy must be there. Good thinking, but physics prevails. For example we just built a building with sides 10'x20',http://www.flickr.com/photos/dynamics/ and the load computation of a wind at 60 mph is 1 ton on a 200 sq ft surface, being a shear force on the foundation, which is 10#/sq ft. That might sound like alot but in terms of pressure per sq. inch it's, Per sq. inch, divide 10# by 144 = lbs/ sq. inch, ~ .07# / sq. inch. By comparision, sea level pressure is 15#/sq.inch, which is convertible to Hg units. Ramming air increases pressure with speed squared so at 120 mph, pressure is 40#/sq. ft etc. So at 420 mph, ram pressure is up to 3.5 #/sq in. which is about a low as is practical, as in a V-1 buzz bomb. Cheers Ken |
#4
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Ram air
On Jun 1, 4:39 pm, Tina wrote:
The induction port for the ram air on the m20J bypasses the air filter as well, so we typically observe about a half inch improvement in MP. That's in line with some of the other numbers offered here. I guess there's no free lunch. There is no way we want to have an IO540 pull the airplane along, nor do we want the fuss with turbo charging. The payback for our typical for real flight mission is just not there. My thought was and is that if it was something pretty obvious someone would have done it on a homebuilt. Actually, knowing some of those guys, it does not have to be obvious at all, they are really creative designers. Tina, I think this analysis you posted is good, " It's only a 360 cubic inch engine turning at 2300 RPM or so. Isn't that a demand of, let's see, at 23 inches mp at sea level that's 23/30 * 2300/2 * 360 / 12^3 or 180 cubic feet a minute? " I see Tango 2 Denny has some interesting ideas. Ken |
#5
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Ram air
On Jun 2, 12:01 pm, "Ken S. Tucker" wrote:
On Jun 1, 4:39 pm, Tina wrote: The induction port for the ram air on the m20J bypasses the air filter as well, so we typically observe about a half inch improvement in MP. That's in line with some of the other numbers offered here. I guess there's no free lunch. There is no way we want to have an IO540 pull the airplane along, nor do we want the fuss with turbo charging. The payback for our typical for real flight mission is just not there. My thought was and is that if it was something pretty obvious someone would have done it on a homebuilt. Actually, knowing some of those guys, it does not have to be obvious at all, they are really creative designers. Tina, I think this analysis you posted is good, " It's only a 360 cubic inch engine turning at 2300 RPM or so. Isn't that a demand of, let's see, at 23 inches mp at sea level that's 23/30 * 2300/2 * 360 / 12^3 or 180 cubic feet a minute? " I see Tango 2 Denny has some interesting ideas. Ken Well, I think it's a dead issue for us. What is fun to think about is, let's see, about 200 cubic feet a minute, that's 40 cubic feet of oxygen a minute, or about 3 pounds. For 50% more O2, 1.5 pounds a minute, or say 20 pounds to get to a pleasantly high altitude. Maybe that translates in to dewer weighing a total of 50 pounds with liquid O2? But it would make 15 inches of MP look like 22 or so as far as the engine is concerned. I better get back to my day job. Resolved: psychologists should not be permitted to minor in the physical sciences. All in favor? |
#6
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Ram air
On Jun 2, 10:13 am, Tina wrote:
On Jun 2, 12:01 pm, "Ken S. Tucker" wrote: On Jun 1, 4:39 pm, Tina wrote: The induction port for the ram air on the m20J bypasses the air filter as well, so we typically observe about a half inch improvement in MP. That's in line with some of the other numbers offered here. I guess there's no free lunch. There is no way we want to have an IO540 pull the airplane along, nor do we want the fuss with turbo charging. The payback for our typical for real flight mission is just not there. My thought was and is that if it was something pretty obvious someone would have done it on a homebuilt. Actually, knowing some of those guys, it does not have to be obvious at all, they are really creative designers. Tina, I think this analysis you posted is good, " It's only a 360 cubic inch engine turning at 2300 RPM or so. Isn't that a demand of, let's see, at 23 inches mp at sea level that's 23/30 * 2300/2 * 360 / 12^3 or 180 cubic feet a minute? " I see Tango 2 Denny has some interesting ideas. Ken Well, I think it's a dead issue for us. What is fun to think about is, let's see, about 200 cubic feet a minute, that's 40 cubic feet of oxygen a minute, or about 3 pounds. For 50% more O2, 1.5 pounds a minute, or say 20 pounds to get to a pleasantly high altitude. Maybe that translates in to dewer weighing a total of 50 pounds with liquid O2? But it would make 15 inches of MP look like 22 or so as far as the engine is concerned. I better get back to my day job. Without crackin' the books and pounding the abacus, you look like +/- 20% using BoE (Back of Envelope) calculation, which means you get either 80% or 120% on your physics exam, you choose. Resolved: psychologists should not be permitted to minor in the physical sciences. All in favor? OR pilots should not be permitted to engage in psychology in this group, now what's the chances of that happening...is "nil" close :-). Ken PS: What's the rationale of the 12,000' cruise? You know about the "bends" don't you, if not just read Berties post! |
#7
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Ram air
On Jun 2, 10:01 am, "Ken S. Tucker" wrote:
Tina, I think this analysis you posted is good, " It's only a 360 cubic inch engine turning at 2300 RPM or so. Isn't that a demand of, let's see, at 23 inches mp at sea level that's 23/30 * 2300/2 * 360 / 12^3 or 180 cubic feet a minute? " Can't do it that way. You're assuming a volumetric efficiency of 100% which we never attain without considerable boosting. The volumetric efficiency at full throttle and redline RPM at sea level isn't likely to be much more than 50 or 60%. Got to do it using fuel flow. Best power mixture comes at around 12:1 (pounds of air to pounds of fuel) and stoichiometric mixture (no wasted air or fuel) is 15:1. Weight of air at sea level is about .078 pounds per cubic foot, and weight of gasoline is 6 lb per US gallon. An O-320 @ 2700 RPM @ S.L. = Displacement of 15,000 cubic feet per hour. Full throttle fuel flow of 10.3 GPH @ 12:1 best power = 9434 cu. ft./hr (with fixed-pitch prop). 9434 ÷ 15,000 = .629 (62.9%) volumetric efficiency @ sea level. Not very good, is it? Air has viscosity and the drag of the entire induction system, even with the throttle wide open, is significant. Add to that the inertia of the air, and the intake valve's opening and closing causing the stop-go action of the air in the system, and things get slowed down considerably. It's worse in auto engines that turn at high RPM. That's why many have four valves per cylinder, or turbos, or both. Dan |
#8
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Ram air
I think we're close to a stoichiometric mixture at peak egt for a
given rpm, but finding a way of stuffing more O2 into the cylinders would be nice during a climb to altitude. Never the less the back of the envelope number crunching I did and others have commented on pretty much convinced me to let engine optimization to those who know what they are doing. I will not be connecting the exhaust of a shop vac to the intake manifold any time soon! And to be honest I did not use the back of an envelope, but a cell in an Excel spreadsheet being used for a different kind of data analysis. Which reminds me, I had better delete it before I pass that analysis around. me Ken S. Tucker" wrote: Tina, I think this analysis you posted is good, " It's only a 360 cubic inch engine turning at 2300 RPM or so. Isn't that a demand of, let's see, at 23 inches mp at sea level that's 23/30 * 2300/2 * 360 / 12^3 or 180 cubic feet a minute? " Can't do it that way. You're assuming a volumetric efficiency of 100% which we never attain without considerable boosting. The volumetric efficiency at full throttle and redline RPM at sea level isn't likely to be much more than 50 or 60%. Got to do it using fuel flow. Best power mixture comes at around 12:1 (pounds of air to pounds of fuel) and stoichiometric mixture (no wasted air or fuel) is 15:1. Weight of air at sea level is about .078 pounds per cubic foot, and weight of gasoline is 6 lb per US gallon. An O-320 @ 2700 RPM @ S.L. = Displacement of 15,000 cubic feet per hour. Full throttle fuel flow of 10.3 GPH @ 12:1 best power = 9434 cu. ft./hr (with fixed-pitch prop). 9434 ÷ 15,000 = .629 (62.9%) volumetric efficiency @ sea level. Not very good, is it? Air has viscosity and the drag of the entire induction system, even with the throttle wide open, is significant. Add to that the inertia of the air, and the intake valve's opening and closing causing the stop-go action of the air in the system, and things get slowed down considerably. It's worse in auto engines that turn at high RPM. That's why many have four valves per cylinder, or turbos, or both. Dan |
#9
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Ram air
On Jun 1, 3:35*am, Tina wrote:
The Mooney 201 has a ram air port, a half a foot under the prop spinner. The POH tells us it can be opened at altitude for a very modest increase in MP and we find maybe a half inch increase in pressure. The idea of the thing is, if the port is looking right at the air being thrust toward it by the prop (it can't be more than 6 inches or so behind it) *as well as the air impact from the airplane's motion the air being 'rammed' into it should effectively lower the altitude the engine thinks it's at. Well, a half inch of Hg is about 500 feet or so. The question is, though, wouldn't you think there would be a way to capture a great deal more of the ram air effect and really boost the engine performance? Who wouldn't like to fly at 24 square at 12000 feet without a turbo charger? Its really to make up for a design flaw in the induction system. Most induction systems don't have the resistance of a Mooney. By the 201 Mooney had mostly fixed this so the ram air makes no noticable difference in the MP. On the pre-201's it adds 3/4 of a inch. -Robert, Mooney CFII |
#10
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Ram air
On Jun 1, 4:35 am, Tina wrote:
The Mooney 201 has a ram air port, a half a foot under the prop spinner. The POH tells us it can be opened at altitude for a very modest increase in MP and we find maybe a half inch increase in pressure. The idea of the thing is, if the port is looking right at the air being thrust toward it by the prop (it can't be more than 6 inches or so behind it) as well as the air impact from the airplane's motion the air being 'rammed' into it should effectively lower the altitude the engine thinks it's at. Well, a half inch of Hg is about 500 feet or so. The question is, though, wouldn't you think there would be a way to capture a great deal more of the ram air effect and really boost the engine performance? Who wouldn't like to fly at 24 square at 12000 feet without a turbo charger? What makes me wonder about it is, even at 60 mph holding your hand out of the window of a car subjects it to a significant backward pressure, so the energy must be there. The energy is there but it's no bigger than what Mooney claims. Flat-plate drag at 100 knots is 29 pounds; dicide that by 144 square inches and get around 0.2 psi, or about 0.4" Hg. Not much. AT 200 knots it will be four times that, which still isn't a lot. In the 1970's Ford sold some cars with "Ram-Air Induction" systems. A scoop mounted on the carb that stuck out above the hood, to ram vast volumes of air into the carb and get way more horsepower. That's what they wanted you to believe. At 60 mph the pressure recovery would have been laughably tiny, but Ford's profits were impressive. On airplanes like the Cessna singles, the air intake faces forward but it doesn't get much ram advantage. The airflow striking the cowling is deflected around it, which means that the airflow in the vicinity of the intake is across that intake, not ramming directly against it. Since Mr. Bernoulli told us that pressure drops with velocity, the pressure at the face of the air filter is likely lower than ambient. Homebuilders can tackle that to some degree and get some improvements in manifold pressure, but those improvements will come mostly as a result of airflow control, not ram recovery. And a funnel, contrary to popular belief, does not increase the pressure within it when facing the airflow. It increases velocity, which must decrease pressure. It's a convergent duct. A divergent duct, on the other hand, slows the airflow and increases pressure, and we find such shapes on jet engine intake ducts, where the cross- section increases just ahead of the fan or first compressor stage. See http://www.aoxj32.dsl.pipex.com/NewF...TWPhysics.html and http://www.thaitechnics.com/engine/e...struction.html Dan |
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