1984 Mooney M20K 231 for sale

"kgruber" wrote in message
...

Matt, you said "Let's see: % of HP = GPH * 14.9, so figure what the power
level. "

Deakin says
"Multiplying the fuel flow (18.0 GPH) by 14.9 (the constant for this
engine), we know this is 268 HP, or a whopping 89%."
http://www.avweb.com/news/columns/182105-1.html

It's HP=GPH*14.9
Not % of HP = GPH * 14.9

And that relationship holds LOP ONLY!

Argue with Deakin, not me.

268 of 285 = 89%

Still the same ****head you were a year or so ago, huh?

A good place to learn about LOP operations and engine operations in general
is on Avweb.

You need to get your facts straight before you start calling names.
Karl
"Curator" N185KG

"Matt Barrow" wrote in message
...

"kgruber" wrote in message
...

Matt, you said "Let's see: % of HP = GPH * 14.9, so figure what the
power level. "

Deakin says
"Multiplying the fuel flow (18.0 GPH) by 14.9 (the constant for this
engine), we know this is 268 HP, or a whopping 89%."
http://www.avweb.com/news/columns/182105-1.html

It's HP=GPH*14.9
Not % of HP = GPH * 14.9

And that relationship holds LOP ONLY!

Argue with Deakin, not me.

268 of 285 = 89%

Still the same ****head you were a year or so ago, huh?