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#21
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wrote in message
ups.com... You're still assuming he's leading the ME-109 as if the gunner were in a fixed location. He's assuming the gunner is actually trying to hit the plane, and smart enough to figure out how so that he times his shot *correctly*. You're both assuming he fires straight back. He can hit the Me-109 by firing straight back, but ONLY if he fires exactly as B-17 crosses the flight path of the Me-109, and only if the Me-109 is fast enough or close enough to get there before the bullet drops out of the flight path of the Me-109. If the Me-109 is at a range of 50 yards, and no slower than the bullet the bullet will be no more than 7 inches lower than the muzzle of the gun and will still hit the Me-109 assuming the two planes are at the same altitude. Fred............... I'll say it again - you misunderstand the question. I have stated it as clearly as I am able and even drawn a diagram. I don't know how else to explain it. I'm a pilot. I talk with my hands (hopefully without resorting to certain gestures). The B-17 is flying West. The ME-109 is flying South. They are both at the same altitude. There is no wind. The ME-109 will cross the flight path of the B-17 and the B-17 will, at that moment, be fifty yards from the ME-109. The tail gunner fires his weapon straight behind the B-17. There is no way that he can hit the ME-109, given the stated speed of the B-17 and the muzzle velocity of the bullet. The ME-109 will *always* be fifty yards or more away from the bullet. Always. Rich S. |
#22
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wrote in message
ups.com... The gunner cannot hit the ME-109 given those relative positions and trajectories no matter where he aims. That is the correct answer. If the gunner fires straight back when he is at the aiming point (e.g. re-lable 'aiming point' to be 'firing point' then the bullet will drop straight down from that point, right? If you change the question you may have any answer you wish. Rich "So, we agree?" S. |
#23
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Here's a wacky scenario... why can you fire a gun on the equator
in the direction of the setting sun? I mean, the Earth spins at the equator at around 1,000 miles per hour (24,000 mile circum- ference divided by 24 hr rotation), so why does the bullet exit the barrel at the same velocity no matter what direction you point it in? Hmmm. :-) I think it's because the atmosphere is rotating at the same speed, thus no friction to slow it down or keep it inside the barrel. Yes? No? How does this differ from the first scenario? Dean A. Scott, mfa --------------------------------------- School of Visual Art and Design southern adventist university --------------------------------------- http://www.southern.edu/~dascott |
#24
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wrote)
Won't it drop stairght down toward the manhole cover? (Yes it will.) Gads, you're right! Crap, now it's basically T-ball at the manhole cover. There goes my 1.35 ERA!! Montblack |
#25
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Rich S. wrote: wrote in message ups.com... You're still assuming he's leading the ME-109 as if the gunner were in a fixed location. He's assuming the gunner is actually trying to hit the plane, and smart enough to figure out how so that he times his shot *correctly*. You're both assuming he fires straight back. He can hit the Me-109 by firing straight back, but ONLY if he fires exactly as B-17 crosses the flight path of the Me-109, and only if the Me-109 is fast enough or close enough to get there before the bullet drops out of the flight path of the Me-109. If the Me-109 is at a range of 50 yards, and no slower than the bullet the bullet will be no more than 7 inches lower than the muzzle of the gun and will still hit the Me-109 assuming the two planes are at the same altitude. Fred............... I'll say it again - you misunderstand the question. I have stated it as clearly as I am able and even drawn a diagram. I don't know how else to explain it. I'm a pilot. I talk with my hands (hopefully without resorting to certain gestures). The B-17 is flying West. The ME-109 is flying South. They are both at the same altitude. There is no wind. The ME-109 will cross the flight path of the B-17 and the B-17 will, at that moment, be fifty yards from the ME-109. The tail gunner fires his weapon straight behind the B-17. There is no way that he can hit the ME-109, given the stated speed of the B-17 and the muzzle velocity of the bullet. The ME-109 will *always* be fifty yards or more away from the bullet. Always. Rich S. The way I see it, you are both in agreement. Fred says to hit the 109 he has to fire at the exact time the 17 croses the 109's path. That is correct. In effect he says that to fire as per your example he can't hit it. Harry K |
#26
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#27
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("Dean A. Scott" wrote)
Here's a wacky scenario... why can you fire a gun on the equator in the direction of the setting sun? I mean, the Earth spins at the equator at around 1,000 miles per hour (24,000 mile circum- ference divided by 24 hr rotation), so why does the bullet exit the barrel at the same velocity no matter what direction you point it in? Hmmm. :-) Don't have an answer ...but pointy bullet shaped things + the equator = this link. http://www.qrg.northwestern.edu/projects/vss/docs/Navigation/2-why-launch-from-equator.html "Why is it better to launch a spaceship from near the equator?" Montblack |
#29
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Rich S. wrote:
There is a (magic) B-17 flying along at 560 mph. The tail gunner is out of .50 caliber ammo. He sees a Messerschmitt ME-109 crossing behind the B-17, 50 yards away. He pulls out his trusty .45 Colt auto (muzzle velocity 820 fps) and fires at the Hun when the ME-109 is directly behind the B-17. He leads the Messerschmitt by exactly enough to hit the pilot (if he were firing from a fixed position). Does the bullet exit the muzzle and fall directly to earth? Rich "Scratching my head" S. Forgetting turbulence following the B-17 the bullet would still have a muzzle velocity of 900 FPS, assuming a military load. 50 yards is 50 yards and the Me109 would still be hit assuming proper aim. Whether it does much more than penetrate the canopy I don't know. Put the trailing turbulence back into the scenario and all bets are off. Dan, U.S. Air Force, retired |
#30
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Blueskies wrote:
But just imagine, as the bullet falls to earth, it will remain horizontal for a while due to the gyroscopic spin caused by the rifling... No, the bullet will start dropping due to gravity immediately upon exiting the muzzle. Dan, U.S. Air Force, retired |
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