On Mar 3, 6:15*pm, "Kyle Boatright" wrote:

The air density doesn't change, but the amount of oxygen per cubic foot
does. *Imagine a one cubic foot in size. *It is full of red balls
(nitrogen), white balls(oxygen), and green balls (CO2). *It won't hold
another ball without removing something. *Now, you have to add a bunch of
black balls (H2O). *Which means you have to take out some red, white, and
green ones to make space. *Now your 1 cubic foot box holds less nitrogen,
oxygen, and CO2. *This is essentially what happens when the humidity rises.
What it means to a combustion engine is that the engine won't produce as
much power, because there is less oxygen per cubic foot (or whatever) of
air.

Actually the above just **may** help support what I am thinking but in
an opposite sense..

The balls you describe above are not the same size, therefore if you
remove some of the bigger balls and replace them with smaller balls,
wouldn't that make the air "denser"

Conversly, if you take out the little balls and replace them with
bigger balls, there is more space between the balls making it less
denser.

I figure if the visible was the "bigger balls" in that parcel of air,
as compared to the surrounding air outside the IMC, then the air
inside that cloud would be less dense verifying what I have been
reading?

Does this make any sense?

It does make sense that there would be less air, thus reducing ening
power, which would change the strobing of the prop once entering IMC,
and after leaving it, that power would resume since the visible
moisture now is replaced with air.

Allen