![]() |
If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|
Thread Tools | Display Modes |
#51
|
|||
|
|||
![]()
Rich S. wrote:
"Robert Bonomi" wrote in message ... Moon-quake, Solar flare, "Deck is fouled", I can think of a bunch of reasons that 'divert to alternate' might be required. Controllers on strike, Aliens on runway, Gotcha. No, no. That's a *Mars* bar. This is Luna. And it should be *obvious* that "Almond Joy" is the appropriate one -- "Sometimes you feel like a nut" *DEFINITELY* describes this 'food for thought'. (Don't blame me if you don't like the answer. It was _your_ question, after all. ![]() :O) But, yeah, "glider" -- for lack of a better term. At the landing site, a *BIG* ramp -- with the _upper_ part conforming to the ballistic trajectory you launched into. You have on-board 'maneuvering' thrusters, to tweak you path to the _exact_ ramp trajectory -- a GCA "glide slope" with a *vengeance*. You touch down on the ramp, and roll out, possible friction brakes, possible aircraft-carrier type snubbing cable. You been watching old Evel Knievel tapes I'll bet. You can *try*, but I suggest that -first- you calculate the energy-density of that system. then contemplate the mass requirements, _just_ to power your "forty watt plasma rifle" -- let alone any on-board flight controls, instrumentation, life-support system, etc. Improvements in battery design have been ramping up so quickly in the past few years that I fully expect to see a pink, drum-beating bunny on the Moon! Rich S. Hey, when that happens are ya gonna share what you are drinking? Dan, U.S. Air Force, retired |
#52
|
|||
|
|||
![]()
Rich S. wrote:
"Dan, U.S. Air Force, retired" wrote in message news:rGsWd.24184$Sn6.22376@lakeread03... Hey, they didn't do it that way in "2001 a Space Odyssey" when they cruised across the surface ofthe moon in the moon bus. Wasn't that a monorail or cable-suspended car? Rich "running low on memory" S. No, it had 6 (?) rocket engines aimed downwards. I had the model whan I was in highschool. Dan, U.S. Air Force, retired |
#53
|
|||
|
|||
![]()
On Sun, 06 Mar 2005 14:03:42 +0800, Stealth Pilot wrote:
On Sat, 05 Mar 2005 19:11:22 GMT, Ron Wanttaja wrote: Let's assume an open-cockpit single-seater. Call it 200 lbs for the pilot, another 100 lbs for his suit, 500 pounds of airframe, 20 pounds of avionics, and 50 pounds for batteries and life support supplied. Let's assume our rocket fuel has a specific impulse of 250 seconds. That's a dry weight of about 870 pounds. forgive my iggorance. are we talking earth pounds, moon pounds or mass? and if we are talking mass is it roman catholic, anglican or engineering? Now stop that. :-) what is actually needed is for someone to do a Wright Brothers on gravity. aviation would go another quantum leap forward if we could just negate the aircraft weight without all that drag. it is amazing that with all our progress we havent made one single inroad into understanding or controlling gravity. You've hit the nail right on the head. Right now, space travel is at the equivalent level of the Montgolfier brothers. Chemical rockets are a dead end; the moral equivalent of de Rozier's combination hot air/hydrogen balloon. Heavier than air flight wasn't possible until the invention of the internal combustion engine. Similarly, the true exploitation of space is waiting for a system that will produce good acceleration without the need of tons of fuel. It's sort of in our grasp, now. Chemical fueled engines have Specific Impulses (Isp) in the range of 200-300 seconds. Modern electric propulsion units see ISPs up to about 3000 seconds. What does that mean? Well, I used an Isp of 250 for the thrust-hovering moon buggy. If you recall, it needed 25 million pounds of fuel for Rich's cross-country. With an ISP of 3000, the fuel requirement drops from 25,000,000 pounds...to a bit over 1,000. Yes, about four orders of magnitude. These units are operational *now*...they're used on communications satellites. They produce a lot of thrust for very little fuel, but the actual amount of thrust they produce is minuscule. The commsats use them to compensate for the north-south wobble their orbits get from the uneven distribution of mass within the earth. They need 150 FPS of delta-V per year, and they run the electric propulsion nearly constantly. As you might expect, they require a lot of power. But a dozen miles from Rich's house, a number of airtight spacecraft hulls complete with operational nuclear power plants lie in storage. The Navy calls them, "mothballed submarines." Back when a tsunami hit Hawaii forty or so years ago, they powered Honolulu with the output of *one* of these subs. Cooling them in space, where you don't have access to billions of tons of cold sea water, is left to the good offices of your local thermal engineer. Ron Wanttaja |
#54
|
|||
|
|||
![]()
On Sat, 5 Mar 2005 23:50:23 -0800, "Rich S."
wrote: "Ron Wanttaja" wrote in message .. . "Moon Zero Two", 1969, starring James Olson. Ooh - I'll look that one up! It's known as the first space western.... :-) With a weight increase, the amount of fuel needed increases disproportionately. Also, if you add a second seat, you're always going to have to have a body or ballast in the spot to keep the beast in balance. We'll just make the ship expandable. When you've got a passenger, just unlatch it in the middle and pull the ends out - like you do with the dining table when Grandma's coming. You might be able to do something along those lines...depending on how much acceleration you plan on. Airplanes can tolerate CG shifts because they have horizontal stabilizers at the end of a longish moment arm. Spacecraft don't. However, with a fly by wire control system, you could compensate for weight offsets so the vehicle flies about the same. You could also handle the problem with something Heinlein referred to as "A Space Suit Built for Two." You're not going to be able to work a keyboard, and if you have buttons and whatnot to push, they're going to have to be well separated to ensure you don't punch the wrong one. It's gonna be tough to fly without a pressurized cabin. Who sez the spacesuit can't have a keyboard- or even a joystick? Pull your arms inside and start typing. 'Course the chest area would look like Jayne Mansfield's. Or just make the suit something like the Jim suits used for diving... http://www.divingheritage.com/jimkern.htm Assuming you're not fixed on a Buck Rogers style ship (or even a Space 1999 style ship...) you could make your buggy from a hard-shell space suit. You probably won't look like Jayne, more like Robbie the Robot ("Danger, Rich Shankland!"). Like Robert said, though, we could use a mass driver or other ground-based system to throw the vehicle, and just rely on onboard fuel to land. This drops the required onboard fuel to about 750 pounds. Not too bad. Naw - can't go for the ground based system. What if you want to stop for a picnic on the shore of the Mare? Ohhhh, now you want *floats*.... :-) Well, maybe we *do* have antigravity. After looking at your figures (not that I understand them), did you say that 5,000 fps is orbital velocity at 10 NM MSL? If so, then what speed is orbital velocity at 1,000' MSL (Moon Surface Level)? Cruising at that speed would obviate the need for constant vertical thrust. Half that speed would require less constant vertical thrust than a hover. If you could find a happy medium, perhaps a small fuel cell, plutonium reactor, cold fusion motor, or bag of rocks and Hernadez's 98 mph fast ball would do it. The problem is, the required orbital velocity is based on the spacecraft's distance *from the center of the orbital body*, not its distance above the surface. So the difference is just 30 FPS between orbits 10 NM high and 1000 feet high. And, in fact, the orbital velocity decreases with increased altitude...but, of course, you have to burn fuel to get to the altitude. The 5000 FPS was for a ballistic case, not an orbit. I brute-forced this one to determine the velocity needed...I used an orbit with a 10 nm apogee and pushed the perigee below the surface until I had an orbit where the above-ground portion was approximately 2,000 NM long (it really, REALLY helps to write your own orbit analysis programs). Ron Wanttaja |
#55
|
|||
|
|||
![]()
"Ron Wanttaja" wrote in message
... The problem is, the required orbital velocity is based on the spacecraft's distance *from the center of the orbital body*, not its distance above the surface. So the difference is just 30 FPS between orbits 10 NM high and 1000 feet high. And, in fact, the orbital velocity decreases with increased altitude...but, of course, you have to burn fuel to get to the altitude. The 5000 FPS was for a ballistic case, not an orbit. I brute-forced this one to determine the velocity needed...I used an orbit with a 10 nm apogee and pushed the perigee below the surface until I had an orbit where the above-ground portion was approximately 2,000 NM long (it really, REALLY helps to write your own orbit analysis programs). When I took physics out at the 'Dub, orbits hadn't even been invented yet. I can barely remember attending, much less any of the course content. I'll leave the calculations to the specialists. From a layman's point of view, it appears as though powered flight on our Moon should require *less* power than on Earth. If your linen bag of termite chow can fly in a one-G field on forty horsepower while beating aside air, smog, clouds, bugs and rain, then our moonflitter should be able to paddle along in one-sixth G under a lot less power. If you can carry fuel to go for your hamburger on Earth, then what's the problem out there (other than a scarcity of Mickey D's)? Absence of air should be an advantage in some ways. Riddle me that, O Caped Crusader! |
#56
|
|||
|
|||
![]()
On Sun, 6 Mar 2005 09:17:30 -0800, "Rich S."
wrote: When I took physics out at the 'Dub, orbits hadn't even been invented yet. I can barely remember attending, much less any of the course content. Heck, Rich, you were playing "Rock, Rock, Rock," before paper and scissors had been invented.... From a layman's point of view, it appears as though powered flight on our Moon should require *less* power than on Earth. If your linen bag of termite chow can fly in a one-G field on forty horsepower while beating aside air, smog, clouds, bugs and rain, then our moonflitter should be able to paddle along in one-sixth G under a lot less power. If you can carry fuel to go for your hamburger on Earth, then what's the problem out there (other than a scarcity of Mickey D's)? Absence of air should be an advantage in some ways. Well, vacuum DOES eliminate drag, but as far as everything else is concerned, it, well....sucks. Look at is this way: All aircraft engines are rocket engines. They work by expelling mass, with the amount of thrust depending upon the amount of mass and the speed at which its expelled. "Jet" engines use burning gasses to increase the velocity of the flow, while us poor ol' Fly Baby jockeys have to make do with carving out a piece of air and throwing it backwards. Down here in the soup, the mass to expel backwards is free. On the moon, though, you have to bring that mass with you. So...how much air, in mass, are we talking about? Let's take a look at my Fly Baby. It's got a prop 72 inches in diameter. The pitch is 48 inches...in an ideal world, every turn of the prop blade would shove a chunk of air 72 inches in diameter backwards a distance of 48 inches. How much air is that? Almost 200,000 cubic inches. But of course, that prop isn't 100% efficient. Let's say it's only 1% efficient...that's 2000 cubic inches of air being pushed backwards to provide thrust. How much does that air weigh? About 1.2 kg per cubic meter. That's about 0.000043 lbs/cu-inch. Which is about 0.1 lb of air per prop rev. And...the prop is revolving at about 40 turns per second, so that's about 4 pounds of "propellant" used per second. An hour flight in my airplane uses over 14,000 pounds of "rocket fuel"! Geeze, maybe I better review those Sport Pilot regs again.... :-) Ron "Hypergolic" Wanttaja |
#57
|
|||
|
|||
![]()
"Ron Wanttaja" wrote in message
... On Sun, 6 Mar 2005 09:17:30 -0800, "Rich S." wrote: When I took physics out at the 'Dub, orbits hadn't even been invented yet. I can barely remember attending, much less any of the course content. Heck, Rich, you were playing "Rock, Rock, Rock," before paper and scissors had been invented.... As a teacher's assistant, it was my job to keep the candles lit during the lectures. Down here in the soup, the mass to expel backwards is free. On the moon, though, you have to bring that mass with you. So...how much air, in mass, are we talking about? Lots free photons floating around, though. Do photons have mass? Even a little bit? If they do, couldn't we collect them in the front, accelerate them until their mass becomes ~ infinite, then toss them out the back? Heck, come to think of it, we don't even need protons. If mass increases as velocity closes in on C, all we need for reaction mass is a handful of depleted uranium. If we can toss it away fast enough. I don't suppose that ..50 caliber hawgleg that Ammeter carries would do it. We need a railgun or two. Rich "Thinking about lighter-than-vacuum balloons next" S. P.S. I like that idea about recycling boomers! |
#58
|
|||
|
|||
![]()
In article ,
Rich S. wrote: "Robert Bonomi" wrote in message ... No, no. That's a *Mars* bar. This is Luna. And it should be *obvious* that "Almond Joy" is the appropriate one -- "Sometimes you feel like a nut" *DEFINITELY* describes this 'food for thought'. (Don't blame me if you don't like the answer. It was _your_ question, after all. ![]() :O) [[.. sneck ..]] You been watching old Evel Knievel tapes I'll bet. You've never been required to play "catch" with raw eggs, have you? Seriously, a number of years ago, some engineering school did a variant on the 'package an egg so it won't break when dropped X feet' contest, where the contestants had to build something to _catch_ an egg, w/o breaking it. You can *try*, but I suggest that -first- you calculate the energy-density of that system. then contemplate the mass requirements, _just_ to power your "forty watt plasma rifle" -- let alone any on-board flight controls, instrumentation, life-support system, etc. Improvements in battery design have been ramping up so quickly in the past few years that I fully expect to see a pink, drum-beating bunny on the Moon! Y'know, you could probably *sell* that idea to the copper-top people for an ad campaign. |
#59
|
|||
|
|||
![]()
In article ,
Ron Wanttaja wrote: [snip] So...we have to burn our downward thrusters for four hours. "G" on the Moon is about 5.6 ft/Sec^2. We'd need to burn the same to counter that. Total acceleration required is 5.6 ft/sec^2 x 4 hours x 3600 seconds/hour... about 80,000 FPS, about sixteen times more than a ballistic S/C using a mass driver for launch, and, as a point of interest, almost three times what a spacecraft launch from the *Earth* needs. With the accel/decel Delta-V, our 870-pound spacecraft requires 24.9 *million* pounds of fuel. Doesn't the vehicle get lighter as fuel and oxidizer are consumed, requiring less thrust, lowering the consumption rate... Dan "and-so-on, and-so-on, and-so-on" Nafe danATscuba-trainingDOTnet |
#60
|
|||
|
|||
![]()
On Sun, 06 Mar 2005 23:33:48 -0500, Dan Nafe wrote:
In article , Ron Wanttaja wrote: [snip] So...we have to burn our downward thrusters for four hours. "G" on the Moon is about 5.6 ft/Sec^2. We'd need to burn the same to counter that. Total acceleration required is 5.6 ft/sec^2 x 4 hours x 3600 seconds/hour... about 80,000 FPS, about sixteen times more than a ballistic S/C using a mass driver for launch, and, as a point of interest, almost three times what a spacecraft launch from the *Earth* needs. With the accel/decel Delta-V, our 870-pound spacecraft requires 24.9 *million* pounds of fuel. Doesn't the vehicle get lighter as fuel and oxidizer are consumed, requiring less thrust, lowering the consumption rate... Exactly, but the basic rocket equation takes that into account: Fuel = Initial Mass * (1 - 1/(e^(Delta-V/(ISP * g))) Ron Wanttaja |
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
About the Global Flyer | robert arndt | Military Aviation | 0 | January 11th 04 03:46 AM |
Call your local TV station, get Wright Flyer on the air | Mark James Boyd | Soaring | 0 | December 17th 03 05:09 PM |
Wright Flyer won't fly! | Trent Moorehead | Piloting | 31 | October 18th 03 04:37 PM |
Wright Flyer | Dave Hyde | Home Built | 9 | September 29th 03 05:20 PM |
Arming Global Hawk Draws Conflicting Comments From Pentagon | Larry Dighera | Military Aviation | 5 | July 14th 03 08:51 PM |