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The stagnation temperature I recall is roughly given by the following:
Ts/T1 = (1 + (M^2)/5) "Mike Rapoport" wrote in message link.net... I have flight manuals that give a correction for airspeed and altitude and the numbers are much higher than 3C even though the speeds are below M0.5. In the MU-2, the temp sensor is in the tail section where the cross section of the fusilage is actually decreasing.. I think the problem is only with the numbers that got plugged in. At M = 0.5, you get Ts/T1 = 1.05. In other words a 5% temp rise. 5% of about 273 K is about 13 K, i.e. 13 degC. Is there both a compression and a friction heating of surfaces due to airflow? It's the same phenomenon. The "friction" occurs because the air is brought to stagnation in the boundary layer. Julian Scarfe |
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