Service Volumes of VOR's make no sense

And a screw-up on the equation:

Radio horizon (in miles) equals the square root of [TWO TIMES the aircraft
altitude above the VOR (in feet)].

Jim



"Antoñio" wrote in message
...

The equation for this is
that radio horizon (in miles) equals the square root of the aircraft
altitude above the VOR (in feet).

On Sun, 15 May 2005 at 09:05:01 in message
, RST Engineering
wrote:
And a screw-up on the equation:

Radio horizon (in miles) equals the square root of [TWO TIMES the aircraft
altitude above the VOR (in feet)].

[1] Jim, Doesn't that assume that the number of feet in a mile is
the same as the radius of the earth in miles?

The formula for the tangential horizon distance is

[2] d=(2*r*h + h^2)^0.5

where d is the tangential horizon distance, r is the radius of the earth
and h is the height of the object above the surface. DKr and h all in
the same units. Because the heights we are talking about are small
compared to the radius of the earth the h^2 term can be ignored leaving
what you said.

E&OE :-)
--
David CL Francis

And you asked in another post if you were being pedantic? PEDANTIC? My
guess is that you stay up late at night worrying about whether
anal(-)retentive is hyphenated or not.

Jim



"David CL Francis" wrote in message
...
On Sun, 15 May 2005 at 09:05:01 in message
, RST Engineering
wrote:
And a screw-up on the equation:

Radio horizon (in miles) equals the square root of [TWO TIMES the aircraft
altitude above the VOR (in feet)].

[1] Jim, Doesn't that assume that the number of feet in a mile is
the same as the radius of the earth in miles?