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#1
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The parts you will need are a 10 amp silicon diode, a 10 kilohm quarter watt
resistor, a small PNP transistor, a LED of the appropriate color, and a 470 ohm quarter watt resistor. All these parts are available from Mouser Electronics, DigiKey Electronics, and the rest of the usual suspects. The silicon (NOT schottky, plain silicon) diode goes in series with the wire going to the pitot, anode to switch, cathode to pitot. THe diode will probably require a heat sink. THe emitter of the PNP transistor goes directly to the anode of the diode. One lead of the 10K resistor goes to the cathode of the diode. THe other lead of the resistor goes to the base of the transistor. One lead of the 470 ohm resistor goes to the collector of the PNP transistor. The other lead of the resistor goes to the anode of the LED. The cathode of the LED goes to airframe ground. HOW IT WORKS: When the pitot switch is turned on, 7 amps through the diode will result in about 1 volt drop across the diode. A PNP transistor turns on with 0.5 volts from base to emitter, so the transistor will turn on through the 10K current limiting resistor. When the transistor turns on, it flows current through the 470 ohm current limiting resistor to the LED. If the pitot heater fails there will not be any significant voltage drop across the diode and the PNP transistor will not turn on and the LED will not light. If you can't find a suitable 10 amp diode, a 0.1 ohm 10 watt resistor will do the same job and will probably be cheaper. In either case, I suspect that the pitot heater will be more reliable than the diode OR the resistor, so a false heater-out alarm will be the predominant failure mode. Be careful where you mount the diode or the resistor. Under normal operating conditions, they will get hotter than hell. Jim "iflycozy" wrote in message ups.com... Question to you electrical designer gurus: Here is what I would like to do and Jim Wier suggested that I post this here. I want an indicator on my Cozy homebuilt airplane to show me that my heated pitot is actually working when I turn on the switch on the instrument panel. So, the light will go out (with the switch still in the on position) if the heated pitot stops working for some reasons (but not because it tripped the circuit breaker). So, how can I build such a device or circuit? I would appreciate specific parts or identification of parts as I am an amateur. This is a 12 volt DC system and the heating element draws 7 amps. I know I can not use a LED in series because it would blow the milli-second I turned the unit on. I know I can't use a light or lamp in parallel because it would not indicate if the heated pitot was on or off. So that is my dilemma. Please help. Reply to: |
#2
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Hi Jim,
Question.. Why put the diode in series with the pitot heater power. (Ok, it senses that power if flowing in the heater circuit, but is that necessary?) Couldn't the same thing be accomplished by using the diode as a temperture sensor (thermometer) to decide if the pitot tube was above a certain temperature? No self-heating on the part of the sense diode, and no pitot heat failure if the diode opens up (burns up?). Richard |
#3
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Of course that is another way of doing it, but it involves bonding the diode
thermally to the pitot tube, putting a reference diode somewhere in the same general vicinity of the pitot tube to sense ambient temperature, insuring an ambient airflow over the reference diode, an opamp to sense the 2.5 millivolts/°C change, and all of that stuff. I prefer dumb when I can get away with it. As I recall, the pitot heater gets about 50°C above ambient, so you are messing around trying to detect a little over a tenth of a volt change, which isn't rocket science, but trying to explain it in this newsgroup is. Jim "Richard Lamb" wrote in message oups.com... Hi Jim, Question.. Why put the diode in series with the pitot heater power. (Ok, it senses that power if flowing in the heater circuit, but is that necessary?) Couldn't the same thing be accomplished by using the diode as a temperture sensor (thermometer) to decide if the pitot tube was above a certain temperature? No self-heating on the part of the sense diode, and no pitot heat failure if the diode opens up (burns up?). Richard |
#4
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Hi Jim,
Question.. Why put the diode in series with the pitot heater power. (Ok, it senses that power if flowing in the heater circuit, but is that necessary?) Couldn't the same thing be accomplished by using the diode as a temperture sensor (thermometer) to decide if the pitot tube was above a certain temperature? No self-heating on the part of the sense diode, and no pitot heat failure if the diode opens up (burns up?). Richard |
#5
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Nothing wrong with an old-fashioned ammeter. Dead simple, and tells you
everything you want to know. I have one that was used for prop de-icer amps (not that I use it for that - I actually use it to test solar panels). David Johnson |
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