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![]() "Morgans" wrote: Some people confuse descent with acceleration. A mere constant-rate descent (apprx. zero net force) does nothing to change the analysis. You lack the ability to change real life application into a physics problem. I'm not sure you are in a position to criticize. If you have your engines set to hold constant speed in level flight, then push over into descent, what happens to your speed? There is a brief acceleration until the airplane reaches its new trim speed, then (roughly, omitting other factors such as greater thrust at lower altitudes, ...) it will hold that new higher speed. Case closed. Now you can use some of that acceleration into pushing against the guns. But that acceleration is brief! They won't fire the gun during a pushover maneuver that is changing aircraft pitch (= aim point). What I hope you mean that the accumulated extra speed (= momentum) gives it a greater margin. Indeed, according to one source, the maximum speed for the A10 is in the 400kt range. On the other hand, pulling out of such a dive, after firing at the ground (and thus not too high to start with), would be quite a feat. I'm sure one could cook up some simple equations to wow oneself with the necessary G load. Everyone seems to forget that the guns on an A-10 are only used in 2 to 4 second bursts [...] Only "seems". - FChE |
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