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Thermal Divider



 
 
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  #1  
Old May 29th 06, 11:43 PM posted to sci.electronics.design,rec.aviation.homebuilt
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Default Thermal Divider

If you mount the sensor in a bar that is picking up heat at one end, and
losing heat at the other - you sensor will read somewhere between the two
temperatures. But, if you don't know a lot about the heat transfer rates
at each end, you will not know how the temperature your sensor sees is
related to the temperature you want to measure.


That's exactly the point, Geoff. When I do a resistive divider, it is always
between two "hard" voltages, either a variable voltage and a reference
voltage or a variable voltage and ground. I know what the reference is and
can easily calculate the variable. The thermal reference is not quite so
trivial. It is a function of airflow, ambient temperature, and phase of the
moon.



Think of a series voltage divider with two known resistors in the middle
and an unknown resistor attached to each end. What does the votage
measured at the junction between the two known resistors tell you about
the source voltage?


Absolutely nothing. An equation in one unknown with two degrees of freedom
is insoluble. There are an infinite number of correct answers and an
infinite number of incorrect answers. HOWEVER, if you let me measure the
voltage ACROSS one of those known resistors and THEN the voltage at the
junction, I've got a fighting chance if you know what the bottom end
resistor is tied to.

Jim


  #2  
Old May 30th 06, 12:00 AM posted to sci.electronics.design,rec.aviation.homebuilt
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Default Thermal Divider

"RST Engineering" wrote in message
news
Think of a series voltage divider with two known resistors in the middle
and an unknown resistor attached to each end. What does the votage
measured at the junction between the two known resistors tell you about
the source voltage?


Absolutely nothing. An equation in one unknown with two degrees of
freedom is insoluble. There are an infinite number of correct answers and
an infinite number of incorrect answers. HOWEVER, if you let me measure
the voltage ACROSS one of those known resistors and THEN the voltage at
the junction, I've got a fighting chance if you know what the bottom end
resistor is tied to.


Think of heat flow as current, temperature as voltage, the actual connecton
between your divider and the heat source / sink like unknown resistors
(area, contact, material all make a difference as in a high current circuit)
your bar with the sensor in the middle is like the voltage drop in a
transmission line - flow is a function of area, material, potential. Heat
loss from the bar is a little harder - I guess in a high tension
transmission line there is some leakage to ground across the insulators?

And you thought you didn't know thermodynamics...

fwiw, I think I would just buy a different sensor, eh?

--
Geoff
The Sea Hawk at Wow Way d0t Com
remove spaces and make the obvious substitutions to reply by mail
When immigration is outlawed, only outlaws will immigrate.


  #3  
Old May 30th 06, 01:56 AM posted to sci.electronics.design,rec.aviation.homebuilt
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Default Thermal Divider


"Capt. Geoffrey Thorpe" The Sea Hawk at wow way d0t com wrote in message
...
"RST Engineering" wrote in message news
Think of a series voltage divider with two known resistors in the middle and an unknown resistor attached to each
end. What does the votage measured at the junction between the two known resistors tell you about the source
voltage?


Absolutely nothing. An equation in one unknown with two degrees of freedom is insoluble. There are an infinite
number of correct answers and an infinite number of incorrect answers. HOWEVER, if you let me measure the voltage
ACROSS one of those known resistors and THEN the voltage at the junction, I've got a fighting chance if you know what
the bottom end resistor is tied to.


Think of heat flow as current, temperature as voltage, the actual connecton between your divider and the heat source /
sink like unknown resistors (area, contact, material all make a difference as in a high current circuit) your bar with
the sensor in the middle is like the voltage drop in a transmission line - flow is a function of area, material,
potential. Heat loss from the bar is a little harder - I guess in a high tension transmission line there is some
leakage to ground across the insulators?

And you thought you didn't know thermodynamics...

fwiw, I think I would just buy a different sensor, eh?

--
Geoff
The Sea Hawk at Wow Way d0t Com
remove spaces and make the obvious substitutions to reply by mail
When immigration is outlawed, only outlaws will immigrate.


Maybe use two sensors, one way out at the cold end, and the other 'half way out'. Use some sort of logic to sort out the
cold end and adjust from there...


 




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