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Thermal Divider



 
 
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  #1  
Old May 30th 06, 01:08 AM posted to sci.electronics.design,rec.aviation.homebuilt
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Default Thermal Divider

"Capt. Geoffrey Thorpe" The Sea Hawk at wow way d0t com wrote in message
news
RST Engineering (jw) wrote:
Is it purely a function of the size of the metal piece, or is the type

of
metal part of the equation?

The other thing I don't understand is that if I do a good job of
insulating the metal piece from ambient how it won't eventually come to
the same temperature as the head.


If you mount the sensor in a bar that is picking up heat at one end, and
losing heat at the other - you sensor will read somewhere between the two
temperatures. But, if you don't know a lot about the heat transfer rates

at
each end, you will not know how the temperature your sensor sees is

related
to the temperature you want to measure.

Think of a series voltage divider with two known resistors in the middle

and
an unknown resistor attached to each end. What does the votage measured at
the junction between the two known resistors tell you about the source
voltage?


how about two temp sensors at measured intervals along the insulated bar,
then assuming the temperature gradient is constant along the bar, you can
work out the temp at the cylinder head.

Colin =^.^=


  #2  
Old May 30th 06, 01:48 AM posted to sci.electronics.design,rec.aviation.homebuilt
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Default Thermal Divider

Now THERE'S a hell of a thought. Consider a "bar" three inches long with
sensors at 1 and 2 inches. Betcha the temperature at the head (zero inches)
is (temp 1) plus delta (temp 1 minus temp 2).

Jim


how about two temp sensors at measured intervals along the insulated bar,
then assuming the temperature gradient is constant along the bar, you can
work out the temp at the cylinder head.

Colin =^.^=




  #3  
Old May 30th 06, 01:57 AM posted to sci.electronics.design,rec.aviation.homebuilt
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Default Thermal Divider


"RST Engineering (jw)" wrote in message ...
Now THERE'S a hell of a thought. Consider a "bar" three inches long with sensors at 1 and 2 inches. Betcha the
temperature at the head (zero inches) is (temp 1) plus delta (temp 1 minus temp 2).

Jim


how about two temp sensors at measured intervals along the insulated bar,
then assuming the temperature gradient is constant along the bar, you can
work out the temp at the cylinder head.

Colin =^.^=





Hmmm, just posted that...must be a fairly good way. Think cold junction compensation....


  #4  
Old May 30th 06, 02:13 AM posted to sci.electronics.design,rec.aviation.homebuilt
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Default Thermal Divider

On Mon, 29 May 2006 17:48:07 -0700, the renowned "RST Engineering
\(jw\)" wrote:

Now THERE'S a hell of a thought. Consider a "bar" three inches long with
sensors at 1 and 2 inches. Betcha the temperature at the head (zero inches)
is (temp 1) plus delta (temp 1 minus temp 2).

Jim


Are you assuming negligible heat loss from the bar itself?




Best regards,
Spehro Pefhany
--
"it's the network..." "The Journey is the reward"
Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
  #5  
Old May 30th 06, 02:22 AM posted to sci.electronics.design,rec.aviation.homebuilt
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Default Thermal Divider


"Spehro Pefhany" wrote in message
...
On Mon, 29 May 2006 17:48:07 -0700, the renowned "RST Engineering
\(jw\)" wrote:

Now THERE'S a hell of a thought. Consider a "bar" three inches long with
sensors at 1 and 2 inches. Betcha the temperature at the head (zero

inches)
is (temp 1) plus delta (temp 1 minus temp 2).

Jim


Are you assuming negligible heat loss from the bar itself?


yes if the bar is insulated well enough between the sensors and the head,
maybe with 3 sensors you could comepnsate for the heat loss through the
insulation wich would make for a curved temperature profile along the bar.

Colin =^.^=


 




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