![]() |
If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|
|
Thread Tools | Display Modes |
|
#1
|
|||
|
|||
![]()
Now that's a VERY interesting way of thinking about it.
It's the proper and textbook way to think about it. difficult to keep the ball exactly centered in a 50-degree bank, so I started thinking about whether it's even possible to do this in a 60-degree bank. Of course it is. However, in a steep bank, the rate of turn is mostly controlled by the elevator. No. The rate of turn is controlled by load factor at a given airspeed. You can increase the rate of turn by banking more, or you can pull back on the yoke to increase the load factor (temporarily). In a 60 degree banked turn, you will get a load factor of 2 regardless of what you do with the elevator. If you don't increase the AOA during turn entry however, the aircraft will accelerate and the 60 degree banked turn will occur at a higher airspeed, in a rapid descent. |
#2
|
|||
|
|||
![]() Ron Natalie wrote: Stubby wrote: What causes a plane to turn is the horizontal component of the lift vector. It certainly does not depend on the turn coordinator. What counts is the center of gravity of the plane, not the tail. ...opinion deleted... While the horizontal component of lift is what pulls you to the interior of the turn, the tail is VERY important to actually "turn" the aircraft direction so that the horizontal component continually gets pointed to the center of the turn. The elevator/rudder mechanism is for applying the torques to the plane so it rolls and yaws. Also, as I remember from the first day of physics class, a physical body behaves as a point mass at the center of gravity with 3 translational forces and 3 rotational torques that can be applied to it. The horizontal component of lift behaves like a string tied to a rock being swung around. The string does indeed apply force to the center of gravity of the rock and "points" to the center of the turn. If you put a paint spot on the rock and want to make the spot always face you, the rock will have to yaw at the same rate as you are rotating it around you; consequently something like a rudder will be needed. |
#3
|
|||
|
|||
![]()
Stubby wrote:
The horizontal component of lift behaves like a string tied to a rock being swung around. No, it doesn't. The lift vector points in a direction (roughly) perpendicular to the wing. Nothing causes it to point to the a "center" other than the other aerodynamic surfaces . |
#4
|
|||
|
|||
![]() Ron Natalie wrote: Stubby wrote: The horizontal component of lift behaves like a string tied to a rock being swung around. No, it doesn't. The lift vector points in a direction (roughly) perpendicular to the wing. Nothing causes it to point to the a "center" other than the other aerodynamic surfaces . The lift vector(s) point perpendicular to the wing (s). With a dihedral angle in the two wings there will be horizontal components of the lift vectors and in level flight they will be equal and opposite, canceling. In a turn with the plane banked, it's easy to see how one lift vector will point entirely straight up while the other doubles its horizontal component. This pulls the plane toward the center of the turn. (It sure is easier to explain with a blackboard!) |
|
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
Most reliable homebuilt helicopter? | tom pettit | Home Built | 35 | September 29th 05 02:24 PM |
Tail flapper failure | Veeduber | Home Built | 2 | May 22nd 04 06:52 AM |
Rate of turn indicator on commercial jets (Boeing / Airbus) | Mark | Simulators | 1 | November 1st 03 10:35 AM |
IFR in the 1930's | Dick | Restoration | 26 | September 11th 03 07:42 PM |
Oshkosh Get together Roster - Sign in, please! | Bruce E. Butts | Home Built | 4 | July 26th 03 11:34 AM |