![]() |
If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|
Thread Tools | Display Modes |
|
#1
|
|||
|
|||
![]() "Mxsmanic" wrote in message ... Tony writes: Ah, but if you are capable of the task, you can apply some classical physics to the information provided in the archive and do the analysis yourself. Acceleration is a change in velocity. Climbing from the ground (or from any constant altitude) is a change in vertical velocity (since the initial rate of climb is zero). Therefore climbing involves acceleration. G forces are nothing more than acceleration. Therefore climbing changes G forces. QED. You are correct, but for typical climbing and decending the amount of G away from 1 is so small that as a pilot it is still "1". Entering a climb or a decent moves a G meter such a small amount, you can't see the needle move and you can't feel the small difference in the seat of your pants. There are small G changes in a barrel roll, but not enough to really feel. As a pilot, the manuever is called "1 G". Keep in mind this is in comparison with other aerobatic manuevers that go to routinely 3 to 10 Gs. Danny Deger |
#2
|
|||
|
|||
![]() Danny, you are correct when you say the actual deviation from 1 G is small for climbs, but small isn't good enough. I wanted what we trained in the sciences would call 1, an integer, not 1.00. The problem I could not resolve in entering a climb is not getting the airplane to pitch up 30 degrees and maintaining 1 g into the seat -- it just has to decelerate to do that. I just don't seem to have the degrees of freedom that are needed. Some - Mx is an example -- don't quite understand how to do the analysis, and would rather argue than show where the math I cited is in error. Too bad, it could have been a learning experience for them. Do take a look at the neat family of curves in the citation: it's interesting stuff, and guess what? If the equations of motion are solved in closed form, G is 1, into the seat. On Jan 5, 5:53 pm, "Danny Deger" wrote: "Mxsmanic" wrote in messagenews:bfftp2t07l335t5qr0s08dsdb80vjr1bnt@4ax .com... Tony writes: Ah, but if you are capable of the task, you can apply some classical physics to the information provided in the archive and do the analysis yourself. Acceleration is a change in velocity. Climbing from the ground (or from any constant altitude) is a change in vertical velocity (since the initial rate of climb is zero). Therefore climbing involves acceleration. G forces are nothing more than acceleration. Therefore climbing changes G forces. QED.You are correct, but for typical climbing and decending the amount of G away from 1 is so small that as a pilot it is still "1". Entering a climb or a decent moves a G meter such a small amount, you can't see the needle move and you can't feel the small difference in the seat of your pants. There are small G changes in a barrel roll, but not enough to really feel. As a pilot, the manuever is called "1 G". Keep in mind this is in comparison with other aerobatic manuevers that go to routinely 3 to 10 Gs. Danny Deger |
#3
|
|||
|
|||
![]()
Tony writes:
Some - Mx is an example -- don't quite understand how to do the analysis, and would rather argue than show where the math I cited is in error. Too bad, it could have been a learning experience for them. I've explained the error. You cannot change your rate of climb without accelerating. You cannot accelerate without deviating from 1 G. You cannot maintain a constant rate of climb forever, so you must change the rate of climb from time to time. And any maneuver that changes the rate of climb (which, in practice, is roughly the same as saying any maneuver that changes altitude) will change the G forces. It's very simple, and doesn't require any fancy physics. Do take a look at the neat family of curves in the citation: it's interesting stuff, and guess what? If the equations of motion are solved in closed form, G is 1, into the seat. You can solve all the equations you want, but you cannot escape from the reality I've described above. -- Transpose mxsmanic and gmail to reach me by e-mail. |
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
AOPA Stall/Spin Study -- Stowell's Review (8,000 words) | Rich Stowell | Aerobatics | 28 | January 2nd 09 02:26 PM |
[OT] USA - TSA Obstructing Armed Pilots? | No Spam! | General Aviation | 3 | December 23rd 03 08:53 PM |
rec.aviation.aerobatics FAQ | Dr. Guenther Eichhorn | Aerobatics | 0 | October 1st 03 07:27 AM |
rec.aviation.aerobatics FAQ | Dr. Guenther Eichhorn | Aerobatics | 0 | September 1st 03 07:27 AM |
rec.aviation.aerobatics FAQ | Dr. Guenther Eichhorn | Aerobatics | 0 | August 1st 03 07:27 AM |