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#51
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T o d d P a t t i s t writes:
I do wish people would stop discussing the roll. A pure rolling motion cannot affect the force vector in any way relevant to producing 1 G into the seat. It's certainly true that rolling alone does not change the magnitude of the acceleration vector at axis around which the roll occurs. Mx is right, but I think he misses the point - there's nothing that says we can't start in a steady climb or end in a steady descent. Both have a steady 1G load on the aircraft. Even if you start in a steady climb or descent, you cannot avoid a change in G forces in any maneuver that requires a change in the rate of change of altitude, which includes a typical barrel roll that preserves positive G on the pilot. -- Transpose mxsmanic and gmail to reach me by e-mail. |
#52
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Steve Foley writes:
I believe you could decrease your altitude while banking and maintain 1G from level flight. No matter what you do, at some point you will deviate from 1 G. -- Transpose mxsmanic and gmail to reach me by e-mail. |
#53
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Jose writes:
Tilting the 1G vector back, the nose comes up. Remember: Whenever the vector is not normal to the surface of the planet, its magnitude will vary from 1 G, because it must always contain a 1 G component that is normal to the surface. This is why you cannot enter a 90-degree bank in a coordinated turn, for example. -- Transpose mxsmanic and gmail to reach me by e-mail. |
#54
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Tony writes:
... I can show you how to go from straight and level into a climb maintaining one g into the seat ... Show me. -- Transpose mxsmanic and gmail to reach me by e-mail. |
#55
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Tony writes:
I made a mistatement in my prior post. I do not know how to get into a 30 degree climb from straight and level without experiencing a change in preceived G forces. Ah, I am reassured. In fact, any change in climb rate requires a change in G. So unless your aerobatic maneuver can be executed without any change in your climb rate at any point, it will involve a change in G. -- Transpose mxsmanic and gmail to reach me by e-mail. |
#56
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![]() "Mxsmanic" wrote in message ... Tony writes: Ah, but if you are capable of the task, you can apply some classical physics to the information provided in the archive and do the analysis yourself. Acceleration is a change in velocity. Climbing from the ground (or from any constant altitude) is a change in vertical velocity (since the initial rate of climb is zero). Therefore climbing involves acceleration. G forces are nothing more than acceleration. Therefore climbing changes G forces. QED. You are correct, but for typical climbing and decending the amount of G away from 1 is so small that as a pilot it is still "1". Entering a climb or a decent moves a G meter such a small amount, you can't see the needle move and you can't feel the small difference in the seat of your pants. There are small G changes in a barrel roll, but not enough to really feel. As a pilot, the manuever is called "1 G". Keep in mind this is in comparison with other aerobatic manuevers that go to routinely 3 to 10 Gs. Danny Deger |
#57
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![]() Danny, you are correct when you say the actual deviation from 1 G is small for climbs, but small isn't good enough. I wanted what we trained in the sciences would call 1, an integer, not 1.00. The problem I could not resolve in entering a climb is not getting the airplane to pitch up 30 degrees and maintaining 1 g into the seat -- it just has to decelerate to do that. I just don't seem to have the degrees of freedom that are needed. Some - Mx is an example -- don't quite understand how to do the analysis, and would rather argue than show where the math I cited is in error. Too bad, it could have been a learning experience for them. Do take a look at the neat family of curves in the citation: it's interesting stuff, and guess what? If the equations of motion are solved in closed form, G is 1, into the seat. On Jan 5, 5:53 pm, "Danny Deger" wrote: "Mxsmanic" wrote in messagenews:bfftp2t07l335t5qr0s08dsdb80vjr1bnt@4ax .com... Tony writes: Ah, but if you are capable of the task, you can apply some classical physics to the information provided in the archive and do the analysis yourself. Acceleration is a change in velocity. Climbing from the ground (or from any constant altitude) is a change in vertical velocity (since the initial rate of climb is zero). Therefore climbing involves acceleration. G forces are nothing more than acceleration. Therefore climbing changes G forces. QED.You are correct, but for typical climbing and decending the amount of G away from 1 is so small that as a pilot it is still "1". Entering a climb or a decent moves a G meter such a small amount, you can't see the needle move and you can't feel the small difference in the seat of your pants. There are small G changes in a barrel roll, but not enough to really feel. As a pilot, the manuever is called "1 G". Keep in mind this is in comparison with other aerobatic manuevers that go to routinely 3 to 10 Gs. Danny Deger |
#58
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#59
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Duncan writes:
??? I simply meant that I see no advantage to logging hours. How do you know? Flown a plane already? If not, you have no evidence to make such a comparison. I'm already certain. A full-motion sim would be more fun than a non-motion sim, in most cases, and it would have none of the drawbacks of flying a real aircraft. -- Transpose mxsmanic and gmail to reach me by e-mail. |
#60
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Tony writes:
Some - Mx is an example -- don't quite understand how to do the analysis, and would rather argue than show where the math I cited is in error. Too bad, it could have been a learning experience for them. I've explained the error. You cannot change your rate of climb without accelerating. You cannot accelerate without deviating from 1 G. You cannot maintain a constant rate of climb forever, so you must change the rate of climb from time to time. And any maneuver that changes the rate of climb (which, in practice, is roughly the same as saying any maneuver that changes altitude) will change the G forces. It's very simple, and doesn't require any fancy physics. Do take a look at the neat family of curves in the citation: it's interesting stuff, and guess what? If the equations of motion are solved in closed form, G is 1, into the seat. You can solve all the equations you want, but you cannot escape from the reality I've described above. -- Transpose mxsmanic and gmail to reach me by e-mail. |
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