Zero G profile

"Mxsmanic" wrote in message
...

A zero-G parabola is a ballistic trajectory; it always involves
acceleration
towards the ground (in the direction of gravity) at exactly 1.0 G. That's
how
it produces the "zero-G" effect.

This being so, you cannot change the acceleration of the aircraft along
the
vertical axis without losing the zero-G effect.

Essentially, if you fire a cannonball next to the aircraft, your aircraft
needs to follow the same path as the cannonball in order to become
"weightless."


Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.

Maxwell writes:

Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.

Accelerating excessively would destroy the zero-G trajectory.

--
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"Mxsmanic" wrote in message
...
Maxwell writes:

Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.

Accelerating excessively would destroy the zero-G trajectory.


Has "zip" to do with the subject at hand. Learn to read.

Mxsmanic wrote in
:

Maxwell writes:

Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.

Accelerating excessively would destroy the zero-G trajectory.

You;re an idiot.


Bertie

I'm sure he meant to reduce power in order to not exceed Vne.

mike

"Maxwell" wrote in message
m...

"Mxsmanic" wrote in message
...

A zero-G parabola is a ballistic trajectory; it always involves
acceleration
towards the ground (in the direction of gravity) at exactly 1.0 G.
That's how
it produces the "zero-G" effect.

This being so, you cannot change the acceleration of the aircraft along
the
vertical axis without losing the zero-G effect.

Essentially, if you fire a cannonball next to the aircraft, your aircraft
needs to follow the same path as the cannonball in order to become
"weightless."


Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.

mike regish writes:

I'm sure he meant to reduce power in order to not exceed Vne.

You reach Vne quickly in a parabola. Remember, you have to accelerate
downwards at 1 G in order to maintain the zero-G state. In five seconds your
rate of descent from the top of the parabola must be 9600 fpm, or 95 kts
_straight down_ (and thus much faster if you are also moving forward).

--
Transpose mxsmanic and gmail to reach me by e-mail.

Mxsmanic wrote in
:

mike regish writes:

I'm sure he meant to reduce power in order to not exceed Vne.

You reach Vne quickly in a parabola.

No, you don't moron


Bertie