Zero G profile

"Mxsmanic" wrote in message
...
Maxwell writes:

Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.

Accelerating excessively would destroy the zero-G trajectory.


Has "zip" to do with the subject at hand. Learn to read.

Uhh..hate to burst your bubble again, but -1 g would have you straining at
your seatbelt with a force of 1 g. If you're not wearing one, you would be
exerting 1 g against the roof.

mike

"Mxsmanic" wrote in message
...
JGalban via AviationKB.com writes:

That's what I do. Keeps me from accelerating excessively in the dive.

Your acceleration is fixed in a parabola. It is always exactly -1.0 G,
which
precisely negates the pull of gravity and gives you the zero gravity
objective.

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I'm sure he meant to reduce power in order to not exceed Vne.

mike

"Maxwell" wrote in message
m...

"Mxsmanic" wrote in message
...

A zero-G parabola is a ballistic trajectory; it always involves
acceleration
towards the ground (in the direction of gravity) at exactly 1.0 G.
That's how
it produces the "zero-G" effect.

This being so, you cannot change the acceleration of the aircraft along
the
vertical axis without losing the zero-G effect.

Essentially, if you fire a cannonball next to the aircraft, your aircraft
needs to follow the same path as the cannonball in order to become
"weightless."


Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.

mike regish writes:

I'm sure he meant to reduce power in order to not exceed Vne.

You reach Vne quickly in a parabola. Remember, you have to accelerate
downwards at 1 G in order to maintain the zero-G state. In five seconds your
rate of descent from the top of the parabola must be 9600 fpm, or 95 kts
_straight down_ (and thus much faster if you are also moving forward).

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mike regish writes:

Uhh..hate to burst your bubble again, but -1 g would have you straining at
your seatbelt with a force of 1 g.

+1 G plus -1 G equals 0 G. In the zero-G state, you're accelerating downward
at 1 G, thus -1 G vertically. Since the acceleration due to gravity is +1 G,
they cancel, and the result is weightlessness.

If you're not wearing one, you would be
exerting 1 g against the roof.

You'll want to heavily pad the entire cabin, anyway, since the return to the 1
G state (and often higher than that, since you must pull out of the parabola)
can be abrupt.

--
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"Mxsmanic" wrote in message
...
mike regish writes:

Uhh..hate to burst your bubble again, but -1 g would have you straining
at
your seatbelt with a force of 1 g.

+1 G plus -1 G equals 0 G. In the zero-G state, you're accelerating
downward
at 1 G, thus -1 G vertically. Since the acceleration due to gravity is +1
G,
they cancel, and the result is weightlessness.

You're accelerating downward at exactly 1 g, or 32 feet per second per
second. Zero g is zero g.


If you're not wearing one, you would be
exerting 1 g against the roof.

You'll want to heavily pad the entire cabin, anyway, since the return to
the 1
G state (and often higher than that, since you must pull out of the
parabola)
can be abrupt.

My seat belt can hold me in quite nicely at zero g. Even at -1 g, which
would have me exerting a 1 g force against the belt. I'm not flying the
freakin' vomit comet. I'm in a freakin' Tripacer and we're all strapped in.

Again...1 g is straight and level. Zero g is downward acceleration at 32
feet per second per second. -1 g is downward acceleration at 64 feet per
second per second.

mike (I've done it already...in a real plane...just wanted to know how to do
it longer...which I now know how to do thanks to info from a real pilot)
regish

P.S. I don't think I'm going to defend you against your flame club anymore.

Mxsmanic wrote in
:

mike regish writes:

Uhh..hate to burst your bubble again, but -1 g would have you
straining at your seatbelt with a force of 1 g.

+1 G plus -1 G equals 0 G. In the zero-G state, you're accelerating
downward at 1 G, thus -1 G vertically. Since the acceleration due to
gravity is +1 G, they cancel, and the result is weightlessness.

Nope, you're anm idiot.


Bertie

Mxsmanic wrote in
:

mike regish writes:

I'm sure he meant to reduce power in order to not exceed Vne.

You reach Vne quickly in a parabola.

No, you don't moron


Bertie

Mxsmanic wrote in
:

Maxwell writes:

Obviously,,, but it still has "zip" to do with reducing power to avoid
accelerating excessively in the dive.

Accelerating excessively would destroy the zero-G trajectory.

You;re an idiot.


Bertie

Mxsmanic wrote in
:

JGalban via AviationKB.com writes:

That's what I do. Keeps me from accelerating excessively in the
dive.

Your acceleration is fixed in a parabola.

No, it isn't


Bertie