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("Charles Vincent" wrote)
According to SAE studies, aerodynamic drag accounts for 60% of the resistance that must be overcome for highway cruise, with tires being 25% and driveline friction making up the last 15%. Semi: Tires ........... 18 Footprint ..... big per tire Weight ....... 80,000 lbs Drag .......... HUGE!! MPG .......... 5 (loaded) Minivan: Tires ........... 4 Footprint ..... smaller per tire Weight ....... 4,000 lbs (for easy math) Drag .......... MUCH less + no cab/trailer drag MPG .......... 22 I've never really understood why an 800 lb motorcycle/rider gets (only) 50 mpg and a fully loaded semi can get (about) 5 mpg? Motorcycle: Tires ........... 2 Footprint ..... very small per tire Weight ....... 800 lbs (with rider) Drag .......... It's a motorcycle! g MPG ........... 50 Paul-Mont |
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Montblack wrote:
("Charles Vincent" wrote) According to SAE studies, aerodynamic drag accounts for 60% of the resistance that must be overcome for highway cruise, with tires being 25% and driveline friction making up the last 15%. Semi: Tires ........... 18 Footprint ..... big per tire Weight ....... 80,000 lbs Drag .......... HUGE!! MPG .......... 5 (loaded) Minivan: Tires ........... 4 Footprint ..... smaller per tire Weight ....... 4,000 lbs (for easy math) Drag .......... MUCH less + no cab/trailer drag MPG .......... 22 I've never really understood why an 800 lb motorcycle/rider gets (only) 50 mpg and a fully loaded semi can get (about) 5 mpg? Motorcycle: Tires ........... 2 Footprint ..... very small per tire Weight ....... 800 lbs (with rider) Drag .......... It's a motorcycle! g MPG ........... 50 Motorcycles have a terrible coefficient of drag given their shape and the shape of the rider. A fully faired bike is much better, but still much worse than most cars. My K1200LT is one of the better motorcycles and its Cd is above 0.5 with the windshield fully lowered and I believe it is closer to 0.6 with the windshield at the highest setting. So even with the relatively small frontal area as compared to a car (although not as much smaller as you might think as the bike is taller than most cars), the drag coefficient is so high that the total drag is quite high in comparison. Matt |
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Montblack wrote:
I've never really understood why an 800 lb motorcycle/rider gets (only) 50 mpg and a fully loaded semi can get (about) 5 mpg? Motorcycle: Tires ........... 2 Footprint ..... very small per tire Weight ....... 800 lbs (with rider) Drag .......... It's a motorcycle! g MPG ........... 50 Paul-Mont Check this: http://www.bgsoflex.com/airdragchart.html Matt |
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In rec.aviation.piloting Montblack wrote:
("Charles Vincent" wrote) According to SAE studies, aerodynamic drag accounts for 60% of the resistance that must be overcome for highway cruise, with tires being 25% and driveline friction making up the last 15%. Semi: Tires ........... 18 Footprint ..... big per tire Weight ....... 80,000 lbs Drag .......... HUGE!! MPG .......... 5 (loaded) Minivan: Tires ........... 4 Footprint ..... smaller per tire Weight ....... 4,000 lbs (for easy math) Drag .......... MUCH less + no cab/trailer drag MPG .......... 22 I've never really understood why an 800 lb motorcycle/rider gets (only) 50 mpg and a fully loaded semi can get (about) 5 mpg? Motorcycle: Tires ........... 2 Footprint ..... very small per tire Weight ....... 800 lbs (with rider) Drag .......... It's a motorcycle! g MPG ........... 50 The coefficient of drag for motorcycles is usually pretty bad unless they are faired, and it still ain't great. The power required to overcome drag is 1/2(p*v^3*A*C) p is the densitity of the fluid v is the airspeed A is the area C is the coefficient of drag -- Jim Pennino Remove .spam.sux to reply. |
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In rec.aviation.piloting Matt Whiting wrote:
wrote: The coefficient of drag for motorcycles is usually pretty bad unless they are faired, and it still ain't great. Yes. The power required to overcome drag is 1/2(p*v^3*A*C) No. It is v^2 unless they have changed the physics since I was an aero engineering student back in the 70s. Yes. The drag goes up with the square of velocity, the POWER required to overcome the drag goes up as the cube. Force: Fd = 1/2(p*v^2*A*C) Power: Pd = Fd * v = 1/2(p*v^3*A*C) -- Jim Pennino Remove .spam.sux to reply. |
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wrote)
The coefficient of drag for motorcycles is usually pretty bad unless they are faired, and it still ain't great. The power required to overcome drag is 1/2(p*v^3*A*C) p is the densitity of the fluid v is the airspeed A is the area C is the coefficient of drag 80-ft length of the semi (vs.) 8-ft length of the motorcycle Does this play (much) of a role here? Is that role expressed (adequately/sufficiently) in the above formula, through "C" ...drag? Paul-Mont http://www.totalmotorcycle.com/motorcyclespecshandbook/1MotorcycleManufacturer.htm Fun site - make / model / year. My Yamahoppers were both in there. |
#9
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In rec.aviation.piloting Montblack wrote:
wrote) The coefficient of drag for motorcycles is usually pretty bad unless they are faired, and it still ain't great. The power required to overcome drag is 1/2(p*v^3*A*C) p is the densitity of the fluid v is the airspeed A is the area C is the coefficient of drag 80-ft length of the semi (vs.) 8-ft length of the motorcycle Does this play (much) of a role here? Is that role expressed (adequately/sufficiently) in the above formula, through "C" ...drag? The C is the catchall variable that is determinded by the object's overall shape and for all but the most simple shapes (i.e. flat plate, sphere, etc.) determined by measurement. As to what length does specifically, it depends. Smooth sides are going to be less "draggy" than lumpy sides. A flat back end is going to be more "draggy" than a tapered back end. -- Jim Pennino Remove .spam.sux to reply. |
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