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Roy Smith wrote:
In article , wrote: If the JPI is coming out soon, it might be interesting to pull the other meter as well. Connect both of them to a 12 V battery sitting on a table - with the same gauge and lengths of wire - and see what they read. The bench test sounds fine, but the same gauge and lengths of wire part is kind of silly. Quite possibly. However, if I _don't_ say that, somebody will try this test with jumper cables for one meter and two 500 foot spools of 30 gauge wire for the other meter, and then write me an indignant email when they buy a new meter and its reading still doesn't match the other one. As for a reference voltage source, any reasonable DVM you can buy at Radio Shack fo $20 will be more than accurate enough for this kind of work. Precision is cheap. Accuracy costs a little more. Matt Roberds |
#2
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![]() Anytime you are looking for electrical problems, you need to keep in mind Ohm's Law. Voltage is equal to resistance times Current. Reading voltages at various places in the airplane gives you little information other than that the conductor is not entirely disconnected, unless you remember that current flow affects voltage drop. I once forgot this principle and spent money that didn't need spending. The strobe on the tail wasn't working, so I checked to see that there was power available to it by pulling the feed wire off, measuring the voltage there, and finding battery voltage. OK. Must be the strobe's power supply shot. Bought another ($500) and installed it. It didn't work, either. Then I remembered: E=IxR. With the strobe turned on (but not working, of course) I took voltage measurements at the bus (OK), at the circuit breaker's output input terminal (OK), at the breaker's output terminal (not OK!) and realized that the breaker was internally defective. There was full battery voltage there with the power supply disconnected, because the meter requires only a few microamps to drive it and the hundred ohms or so in the breaker's corroded contacts wasn't enough to drop the voltage to it. Connecting the power supply introduced a much lower resistance, increased the current demand to two or three amps, and caused a huge voltage drop so that the strobe was dead. The airplane needed a $15 breaker, not a $500 power supply. Dan |
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On Sep 24, 9:03 am, wrote:
Anytime you are looking for electrical problems, you need to keep in mind Ohm's Law. Voltage is equal to resistance times Current. Reading voltages at various places in the airplane gives you little information other than that the conductor is not entirely disconnected, unless you remember that current flow affects voltage drop. I once forgot this principle and spent money that didn't need spending. The strobe on the tail wasn't working, so I checked to see that there was power available to it by pulling the feed wire off, measuring the voltage there, and finding battery voltage. OK. Must be the strobe's power supply shot. Bought another ($500) and installed it. It didn't work, either. Then I remembered: E=IxR. With the strobe turned on (but not working, of course) I took voltage measurements at the bus (OK), at the circuit breaker's output input terminal (OK), at the breaker's output terminal (not OK!) and realized that the breaker was internally defective. There was full battery voltage there with the power supply disconnected, because the meter requires only a few microamps to drive it and the hundred ohms or so in the breaker's corroded contacts wasn't enough to drop the voltage to it. Connecting the power supply introduced a much lower resistance, increased the current demand to two or three amps, and caused a huge voltage drop so that the strobe was dead. The airplane needed a $15 breaker, not a $500 power supply. Dan I should add: Many batteries get replaced because the engine doesn't crank very well. You need to take voltage drop measurements across the master and starter solenoids while cranking; you'll often find that their contacts are burned and introducing resistance with the large current flow. Resistance checks mean nothing on these things; even a quarter ohm will cost a bunch of voltage, and with large current flows heat is generated, which increases the resistance further. Same goes for cable and terminal crimps and connections. Dan |
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