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On Thu, 24 Apr 2008 12:46:29 GMT, Jay Maynard
wrote in : On 2008-04-24, WingFlaps wrote: When will pilots learn to stop trying to do the impossible turn... and go for a straight ahead landing on soemthing horizontal? Depends on what you mean by "the impossible turn". If you mean turning back at 200 AGL, yeah, that one's pretty much impossible. If you mean 600 AGL, it's pretty much possible in the average aircraft. (Hell, that's pattern altitude at EFD!) The line lies somewhere in between. This subject has been discussed in detail with the assistance of erudite professor Lowry's input: http://groups.google.com/group/rec.a...1d80a2e846a88b John T. Lowry Best turnaround bank angle phi (least altitude loss per angle turned through) for a gliding airplane is given by: cos(phi) = (sqrt(2)/2)*sqrt(1-k^2) where k = CD0/CLmax + CLmax/(pi*e*A) where CD0 is the parasite drag coefficient, CLmax is the maximum lift coefficient for the airplane's flaps configuration, e is the airplane efficiency factor, and A is the wing aspect ratio. I know most ng readers hate those darned formulas, but that's the way the world works. For GA propeller-driven airplanes, k is a small number (0.116 for a Cessna 172, flaps up) and so the best turnaround bank angle is very closely the 45 degrees cited by Rogers and, much earlier, by Langewiesche (Stick and Rudder, p. 358). For the above Cessna, for instance, it's 45.4 degrees. For a flamed-out jet fighter, however, things are considerably different. The formulas above, along with formulas for the banked stall speed, for banked gliding flight path angle, and for the minimum altitude loss in a 180-degree turn, can all be found in my recent book Performance of Light Aircraft, pp. 294-296. The following seven pages then treat the return-to-airport maneuver, from start of the takeoff roll to contact with the runway or terrain, in excruciating detail. Including wind effects, the typical four-second hesitation when the engine stops, etc. John. -- John T. Lowry, PhD Flight Physics; Box 20919; Billings MT 59104 Voice: 406-248-2606 Nov 1 1999, 1:00 am Newsgroups: rec.aviation.piloting, rec.aviation.student From: "John T. Lowry" Date: 1999/11/01 Subject: Turn Back Maneuver Best turnaround bank angle phi (least altitude loss per angle turned through) for a gliding airplane is given by: cos(phi) = (sqrt(2)/2)*sqrt(1-k^2) where k = CD0/CLmax + CLmax/(pi*e*A) where CD0 is the parasite drag coefficient, CLmax is the maximum lift coefficient for the airplane's flaps configuration, e is the airplane efficiency factor, and A is the wing aspect ratio. I know most ng readers hate those darned formulas, but that's the way the world works. For GA propeller-driven airplanes, k is a small number (0.116 for a Cessna 172, flaps up) and so the best turnaround bank angle is very closely the 45 degrees cited by Rogers and, much earlier, by Langewiesche (Stick and Rudder, p. 358). For the above Cessna, for instance, it's 45.4 degrees. For a flamed-out jet fighter, however, things are considerably different. The formulas above, along with formulas for the banked stall speed, for banked gliding flight path angle, and for the minimum altitude loss in a 180-degree turn, can all be found in my recent book Performance of Light Aircraft, pp. 294-296. The following seven pages then treat the return-to-airport maneuver, from start of the takeoff roll to contact with the runway or terrain, in excruciating detail. Including wind effects, the typical four-second hesitation when the engine stops, etc. John. -- John T. Lowry, PhD Flight Physics; Box 20919; Billings MT 59104 Voice: 406-248-2606 Mo http://groups.google.com/group/rec.a...4829291b24775f http://groups.google.com/group/rec.a...c37fab40401aba http://groups.google.com/group/rec.a...73917967e58181 http://groups.google.com/group/rec.a...b42a74fe660741 http://groups.google.com/group/rec.a...73917967e58181 http://groups.google.com/groups/sear...X-Y_&filter=0& http://groups.google.com/group/rec.a...095b7459a04b3a |
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theyr are ignoring u boooring
Larry Dighera pretended : John T. Lowry |
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