![]() |
If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|
Thread Tools | Display Modes |
|
#1
|
|||
|
|||
![]()
On Jun 8, 5:08*pm, Le Chaud Lapin wrote:
Hi All, This post is primarily directed toward student pilots like myself. First, I am not asking because I want to know the answer (I already know), but do a little experiment. *I have maybe 7 or 8 different sources of flight information that I rely on for ground school (Jeppesen, FAA Handbooks, etc), and none of them said _how_ it worked in sufficient detail, they only said what one must do to make the plane pitch up or downard. So for you students, please do not cheat and do what I did, which is watch the airfoils move as you move the trim control. *Also, it would help if you did not think about the correct answer too much, which would lead you to the correct answer, thereby defeating the purpose of my experiment. So, without cheating, and without asking an experienced pilot or mechanic,... What exactly happens when the trim is adjusted to point the nose upward? Well, since you frame it as a troll: You scare the lift faries to run forward by waving a very nasty bit of metal at them. YAWN Cheers |
#2
|
|||
|
|||
![]()
One point about the lift fairy sitting on the tail I'd like to
understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. . On Jun 8, 5:18 am, WingFlaps wrote: On Jun 8, 5:08 pm, Le Chaud Lapin wrote: Hi All, This post is primarily directed toward student pilots like myself. First, I am not asking because I want to know the answer (I already know), but do a little experiment. I have maybe 7 or 8 different sources of flight information that I rely on for ground school (Jeppesen, FAA Handbooks, etc), and none of them said _how_ it worked in sufficient detail, they only said what one must do to make the plane pitch up or downard. So for you students, please do not cheat and do what I did, which is watch the airfoils move as you move the trim control. Also, it would help if you did not think about the correct answer too much, which would lead you to the correct answer, thereby defeating the purpose of my experiment. So, without cheating, and without asking an experienced pilot or mechanic,... What exactly happens when the trim is adjusted to point the nose upward? Well, since you frame it as a troll: You scare the lift faries to run forward by waving a very nasty bit of metal at them. YAWN Cheers |
#3
|
|||
|
|||
![]()
Tina wrote:
One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi |
#4
|
|||
|
|||
![]()
On Jun 10, 1:09 pm, Tauno Voipio wrote:
Tina wrote: One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi Thanks for the rule of thumb, Tauno. I have watched how busy the flippers are on fighters when they are in the flare -- no human pilot is working that hard for control. I knew the fighters are designed to be aerodynamically unstable. So the aerodynamic longitudinal stability the tail provides might cost us 5 to 10%, The obvious question is, do canards buy back that fraction? They would be offering positive lift, and if they stall first would provide the same sort of longitudinal stability, wouldn't they? be |
#5
|
|||
|
|||
![]()
Tina wrote:
On Jun 10, 1:09 pm, Tauno Voipio wrote: Tina wrote: One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi Thanks for the rule of thumb, Tauno. I have watched how busy the flippers are on fighters when they are in the flare -- no human pilot is working that hard for control. I knew the fighters are designed to be aerodynamically unstable. So the aerodynamic longitudinal stability the tail provides might cost us 5 to 10%, The obvious question is, do canards buy back that fraction? They would be offering positive lift, and if they stall first would provide the same sort of longitudinal stability, wouldn't they? Yes - they do bring back some, and this is the reasoning behind e.g. Rutan's Voyager, The price is that the canard (front wing) has to stall first unless you want to fall to ground in reverse when the thing stalls. The rumours are that the canards are a PITA to land nicely. -- -Tauno |
#6
|
|||
|
|||
![]()
Thanks again. My intelligent but ignorant guess is designing canards
so that they stall first should not take a genius, but there may be traps I don't see. The world is safe, though, since I don't design airplane. The landing issue you raised is pretty neat, since most of us -- especially Mooney drivers -- are careful about airspeed on final and in the flare, and like to land with the wings almost stalled. But in the case of a canard if that stalls first I think the airplane would very enthusiastically want to pitch forward hard enough to bend the nosewheel! At least with the stabilizer still flying the nose might be able to be put down more gently. You've provided some nice insights, thanks. On Jun 10, 2:14 pm, Tauno Voipio wrote: Tina wrote: On Jun 10, 1:09 pm, Tauno Voipio wrote: Tina wrote: One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since theI center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi Thanks for the rule of thumb, Tauno. I have watched how busy the flippers are on fighters when they are in the flare -- no human pilot is working that hard for control. I knew the fighters are designed to be aerodynamically unstable. So the aerodynamic longitudinal stability the tail provides might cost us 5 to 10%, The obvious question is, do canards buy back that fraction? They would be offering positive lift, and if they stall first would provide the same sort of longitudinal stability, wouldn't they? Yes - they do bring back some, and this is the reasoning behind e.g. Rutan's Voyager, The price is that the canard (front wing) has to stall first unless you want to fall to ground in reverse when the thing stalls. The rumours are that the canards are a PITA to land nicely. -- -Tauno |
#7
|
|||
|
|||
![]()
On Tue, 10 Jun 2008 11:24:39 -0700 (PDT), Tina
wrote: Thanks again. My intelligent but ignorant guess is designing canards so that they stall first should not take a genius, but there may be traps I don't see. The world is safe, though, since I don't design airplane. The landing issue you raised is pretty neat, since most of us -- especially Mooney drivers -- are careful about airspeed on final and in the flare, and like to land with the wings almost stalled. But in the case of a canard if that stalls first I think the airplane would very enthusiastically want to pitch forward hard enough to bend the nosewheel! I haven't flown a canard, but my son has done a lot of flying in one that was under development. You are right... you don't want to stall the canard on landing. You fly it all the way to the ground. Three problems with the canard, as my son saw it, was lack of forward visibility on landing, drag from the canard in cruise flight (a fixed canard has to have its AOA greater than the wing and enough surface to generate lift) and ice shedding off the wings through the propelllor. Piaggio solved the drag problem, partially, with a three surface aircraft and a relatively small canard. I believe Beechcraft attempted to solve it with a variable sweep canard, but I could be wrong. At least with the stabilizer still flying the nose might be able to be put down more gently. You've provided some nice insights, thanks. My son says canard landings are like the "Little girl with the curl in the middle of her forehead"... when they are good, they are very very good, but when they are bad they are horrid. :-) Ron Kelley |
#8
|
|||
|
|||
![]()
On Tue, 10 Jun 2008 11:24:39 -0700 (PDT), Tina wrote:
Thanks again. My intelligent but ignorant guess ???? is designing canards so that they stall first should not take a genius, but there may be traps I don't see. The world is safe, though, since I don't design airplane. The landing issue you raised is pretty neat, since most of us -- especially Mooney drivers -- are careful about airspeed on final and in the flare, and like to land with the wings almost stalled. But in the case of a canard if that stalls first I think the airplane would very enthusiastically want to pitch forward hard enough to bend the nosewheel! Basically you want to set up your speeds so the main gear touches before the canard stalls in a fully flying condition about 85/90 kts. This gives a wide margin before the canard stalls and reduces the sensitivity to Xwinds. Easier than a full-stall landing; all control surfaces are fully functional plne is highly maneuverable all the way to the ground. At least with the stabilizer still flying the nose might be able to be put down more gently. You've provided some nice insights, thanks. Thx. lol |
#9
|
|||
|
|||
![]()
On Tue, 10 Jun 2008 18:14:41 GMT, Tauno Voipio wrote:
Tina wrote: On Jun 10, 1:09 pm, Tauno Voipio wrote: Tina wrote: One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. A rule of thumb is that the force on the horizontal tail is 5 to 10 per cent of the wing lift. This translates to a loss of 10 to 20 per cent of the raw gross lift availbale from the horizontal airfoils. I'm obviously thinking about increased efficiency -- extra weight added because of either fat people, full fuel, or aerodynamically imposed, all cost horsepower (OK, watts for you purists) to move around. This is the reason why modern military aircraft are designed aerodynamically unstable, and the electronic gnomes of the flight control system have to work all they can do. The loss of gross lift is the proce to pay for simple and safe longitudinal stability. -- Tauno Voipio tauno voipio (at) iki fi Thanks for the rule of thumb, Tauno. I have watched how busy the flippers are on fighters when they are in the flare -- no human pilot is working that hard for control. I knew the fighters are designed to be aerodynamically unstable. So the aerodynamic longitudinal stability the tail provides might cost us 5 to 10%, The obvious question is, do canards buy back that fraction? They would be offering positive lift, and if they stall first would provide the same sort of longitudinal stability, wouldn't they? Yes - they do bring back some, and this is the reasoning behind e.g. Rutan's Voyager, The price is that the canard (front wing) has to stall first unless you want to fall to ground in reverse when the thing stalls. The rumours are that the canards are a PITA to land nicely. Apparently only to those who don't know how to fly one. |
#10
|
|||
|
|||
![]()
On Jun 10, 9:29 am, Tina wrote:
One point about the lift fairy sitting on the tail I'd like to understand is this -- actually a serious question. As I understand it, nearly aways the tail is exerting a downward force, since the center of lift is aft of the center of gravity on general aviation airplanes (that is true, isn't it -- that the cg is forward of the center of lift?). If so the tail really is imposing an increased load on the airplane, adding to its effective weight. The question I have is, how many pounds of weight is imposed aerodynamically for an airplane that might be loaded with its CG at the forward limit? I don't know where the center of lift is on ga airplanes -- a third of the way aft of the leading edge of the wing is an ok approximation, but a few inches error on an airplane weighing what ours does at max could make a huge change in the required force to overcome the nose heavy moment. CG range for most typical lightplane airfoils is 25 to 33% of the chord, while the centre of lift is around the 40% mark. The load on the stab/elevator isn't all that big, but it's enough that we'll teach you in groundschool that the aircraft's stall speed is lower when loaded to the aft limit than when it's loaded to the forward limit, and that the cruise speed is a little better at the aft limit. Dan |
Thread Tools | |
Display Modes | |
|
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
F-100 detail | Pjmac35 | Aviation Photos | 0 | July 26th 07 10:29 AM |
Finding "Neutral" Position on Piper Elevator/Trim Tab | [email protected] | Owning | 10 | December 7th 06 01:43 PM |
Detail pops in too late in FS2004 | CatharticF1 | Simulators | 0 | August 27th 03 03:25 AM |