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#1
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On Dec 9, 2:28*pm, brianDG303 wrote:
First, a nit-pick; incandescent lamps are resistive and not inductive and inrush isn't a common component. Sorry wrong nit to pick. The resistance of an incandescent lamp filament is temperature dependent. Anyone that has used lamps as current control devices is well aware of this. Andy |
#2
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On Dec 10, 8:44*am, Andy wrote:
Sorry wrong nit to pick. *The resistance of an incandescent lamp filament is temperature dependent. *Anyone that has used lamps as current control devices is well aware of this. I suppose I should have completed the information. The resistance is low when the filament is cold. There is a large inrush current which reduces as soon as the filament gets hot. Anyone old enough to have used equipment with vacuum tubes (valves or bottles) will remember how bright the heaters glowed when the equipment was first turned on. The thermionic valve was a marvelous device - heat, light, and RF out of one component ![]() Andy |
#3
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OK Andy, I'll bite. Lighting loads are generally considered to be
resistive and not inductive. While not perhaps true in some examples, for the subject of this thread I think the nit was picked correctly. For example, if you connect 16 amps of lighting load to a 20 amp fast fuse (or 'Quick Operating' magnetically enhanced circuit breaker) you will have a reliable circuit. If you connect a 16 amp capacity core and coil transformer to that same fuse, or if you connect 16 amps of old style HID lighting with the reactive ballasts acting as inductors, you will pop that fast fuse most of the time in an AC circuit. I think that if in an AC circuit the contact closure is timed exactly as the sine wave crosses the 0 volt line there is sometimes sufficient lag to slow the inrush enough to keep the fuse from popping. That's my theory anyway. If you still don't buy what I am saying, I'm perfectly happy to concede the point. However, the original post implied that motors and incandescent light bulbs require slow-blow fuses. (Many) motors do and incandescent light bulbs do not, so if you are designing an electrical system and the only "Inductive" loads are incandescent it would be fine to use a fast blow fuse in order to protect electronic gear. I guess this brings up another point, if there is more than one fuse certainly the battery fuse or CB could be a slow blow and the fuses at the gear would want to be fast blow in most cases. On Dec 10, 11:39*am, Andy wrote: On Dec 10, 8:44*am, Andy wrote: Sorry wrong nit to pick. *The resistance of an incandescent lamp filament is temperature dependent. *Anyone that has used lamps as current control devices is well aware of this. I suppose I should have completed the information. *The resistance is low when the filament is cold. *There is a large inrush current which reduces as soon as the filament gets hot. Andy |
#4
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My glider has multiple batteries with a switch to change between them
during flight. To, hopefully, eliminate loss of logger data during the brief interruption of power during the switching process there is a large capacitor to ensure continuity of supply to selected instruments during switching. Although there is a resistor to limit the inrush current to the capacitor this type of circuit needs a slow-blow fuse. (Factory wired in last two years.) |
#5
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This looks like a major clue that changes everything. (Well, almost
everything.) My ASG29 also has two main batteries and a dial switch on the panel that selects which battery is providing power to all of the instruments. I wonder if the transition from B1 to B2 is popping the (fast-blow) fuse on the back of the B40. And it would explain why there was a T500L250V fuse in the panel fuse holder; I understand that the "T" means slow-blow ("T"imed?), where an "F" would indicate fast- blow. 2NO |
#6
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On Dec 11, 9:00*am, Tuno wrote:
I wonder if the transition from B1 to B2 is popping the (fast-blow) fuse on the back of the B40. I have the same factory standard rotary power switch and an unmodifed B40 that is always left on and selected to external power. My B40 fuse has never blown. (There are no external capacitors in my glider nor do I need any). Andy |
#7
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On 10 Dec, 22:53, brianDG303 wrote:
OK Andy, I'll bite. Lighting loads are generally considered to be resistive and not inductive. While not perhaps true in some examples, for the subject of this thread I think the nit was picked correctly. For example, if you connect 16 amps of lighting load to a 20 amp fast fuse (or 'Quick Operating' magnetically enhanced circuit breaker) you will have a reliable circuit. If you connect a 16 amp capacity core and coil transformer to that same fuse, or if you connect 16 amps of old style HID lighting with the reactive ballasts acting as inductors, you will pop that fast fuse most of the time in an AC circuit. I think that if in an AC circuit the contact closure is timed exactly as the sine wave crosses the 0 volt line there is sometimes sufficient lag to slow the inrush enough to keep the fuse from popping. That's my theory anyway. If you still don't buy what I am saying, I'm perfectly happy to concede the point. However, the original post implied that motors and incandescent light bulbs require slow-blow fuses. (Many) motors do and incandescent light bulbs do not, so if you are designing an electrical system and the only "Inductive" loads are incandescent it would be fine to use a fast blow fuse in order to protect electronic gear. I guess this brings up another point, if there is more than one fuse certainly the battery fuse or CB could be a slow blow and the fuses at the gear would want to be fast blow in most cases. On Dec 10, 11:39*am, Andy wrote: On Dec 10, 8:44*am, Andy wrote: Sorry wrong nit to pick. *The resistance of an incandescent lamp filament is temperature dependent. *Anyone that has used lamps as current control devices is well aware of this. I suppose I should have completed the information. *The resistance is low when the filament is cold. *There is a large inrush current which reduces as soon as the filament gets hot. I too vaguely recalled that the initial current in a cold incandescent bulb might be rather high. I cant however remember precisely. It is though easy to find out if you have a bulb and a multimeter. Just measure the resistance when the bulb is cold and check the expected current with V = IR. Well I = V / R. This article http://en.allexperts.com/q/Physics-1...lamp-surge.htm states that the initial current is 10 times the running current for a domestic light bulb. Bulbs used in gliders are likely to run cooler so that they can be tougher to better resist vibration, and so the initial vs final current ratio will likely be lower. The other aspect to this is of course that the bulb does warm up very quickly and so even a fast blow fuse may well be unable to respond quickly enough to fail 'inappropriately'. |
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