A aviation & planes forum. AviationBanter

If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below.

Go Back   Home » AviationBanter forum » rec.aviation newsgroups » Home Built
Site Map Home Register Authors List Search Today's Posts Mark Forums Read Web Partners

visualisation of the lift distribution over a wing



 
 
Thread Tools Display Modes
  #1  
Old December 2nd 09, 04:53 AM posted to rec.aviation.homebuilt
Jim Logajan
external usenet poster
 
Posts: 1,958
Default visualisation of the lift distribution over a wing

Alan Baker wrote:
Because the push is caused by the impact of countless air molecules
with the surface of wing. If those collisions fall to zero (i.e. in a
perfect vacuum) then there is zero push.


I don't see what a change in air density (such as taking the extreme case
of a vacuum) has to do with lift. Unless you are claiming density change as
a requirement?

I believe lift can be reasonably computed using inviscid _incompressible_
flow theory (e.g. as far back as Kutta's 1902 dissertation,) so I don't see
why any change in _density_ - much less the vacuum edge case - needs to be
invoked.
  #2  
Old December 2nd 09, 05:26 AM posted to rec.aviation.homebuilt
Beryl[_3_]
external usenet poster
 
Posts: 52
Default visualisation of the lift distribution over a wing

Jim Logajan wrote:
Alan Baker wrote:
Because the push is caused by the impact of countless air molecules
with the surface of wing. If those collisions fall to zero (i.e. in a
perfect vacuum) then there is zero push.


I don't see what a change in air density (such as taking the extreme case
of a vacuum) has to do with lift.


I'm going to build a thick wing, real thick! About 10,000 feet thick.
While the bottom surface of the wing sits at 29.92" sea level
atmospheric pressure, the upper surface will be *way* up there, in a
lower-pressure area. This airplane is gonna to lift off the ground at
zero airspeed with no power.
  #3  
Old December 2nd 09, 05:51 AM posted to rec.aviation.homebuilt
Steve Hix[_2_]
external usenet poster
 
Posts: 50
Default visualisation of the lift distribution over a wing

In article ,
Beryl wrote:

Jim Logajan wrote:
Alan Baker wrote:
Because the push is caused by the impact of countless air molecules
with the surface of wing. If those collisions fall to zero (i.e. in a
perfect vacuum) then there is zero push.


I don't see what a change in air density (such as taking the extreme case
of a vacuum) has to do with lift.


I'm going to build a thick wing, real thick! About 10,000 feet thick.
While the bottom surface of the wing sits at 29.92" sea level
atmospheric pressure, the upper surface will be *way* up there, in a
lower-pressure area. This airplane is gonna to lift off the ground at
zero airspeed with no power.


Only if you make it from monatomic Unobtanium. Only thing light enough
for the job.
  #4  
Old December 2nd 09, 08:17 AM posted to rec.aviation.homebuilt
Alan Baker
external usenet poster
 
Posts: 244
Default visualisation of the lift distribution over a wing

In article ,
Jim Logajan wrote:

Alan Baker wrote:
Because the push is caused by the impact of countless air molecules
with the surface of wing. If those collisions fall to zero (i.e. in a
perfect vacuum) then there is zero push.


I don't see what a change in air density (such as taking the extreme case
of a vacuum) has to do with lift. Unless you are claiming density change as
a requirement?

I believe lift can be reasonably computed using inviscid _incompressible_
flow theory (e.g. as far back as Kutta's 1902 dissertation,) so I don't see
why any change in _density_ - much less the vacuum edge case - needs to be
invoked.


Any change in pressure is *by definition* a change in the number of
particles in the fluid that are impacting the surface.

I never mentioned density.

--
Alan Baker
Vancouver, British Columbia
http://gallery.me.com/alangbaker/100008/DSCF0162/web.jpg
  #5  
Old December 2nd 09, 05:08 PM posted to rec.aviation.homebuilt
Jim Logajan
external usenet poster
 
Posts: 1,958
Default visualisation of the lift distribution over a wing

Alan Baker wrote:
In article ,
Jim Logajan wrote:

Alan Baker wrote:
Because the push is caused by the impact of countless air molecules
with the surface of wing. If those collisions fall to zero (i.e. in
a perfect vacuum) then there is zero push.


I don't see what a change in air density (such as taking the extreme
case of a vacuum) has to do with lift. Unless you are claiming
density change as a requirement?

I believe lift can be reasonably computed using inviscid
_incompressible_ flow theory (e.g. as far back as Kutta's 1902
dissertation,) so I don't see why any change in _density_ - much less
the vacuum edge case - needs to be invoked.


Any change in pressure is *by definition* a change in the number of
particles in the fluid that are impacting the surface.


That assertion is incorrect. You are no dummy so I'm sure you'll correct it
when you realize the errors.

I never mentioned density.


Sorry, but you used the word "vacuum." The notable characteristic of a
vacuum is that its density is zero.
  #6  
Old December 2nd 09, 06:58 PM posted to rec.aviation.homebuilt
Alan Baker
external usenet poster
 
Posts: 244
Default visualisation of the lift distribution over a wing

In article ,
Jim Logajan wrote:

Alan Baker wrote:
In article ,
Jim Logajan wrote:

Alan Baker wrote:
Because the push is caused by the impact of countless air molecules
with the surface of wing. If those collisions fall to zero (i.e. in
a perfect vacuum) then there is zero push.

I don't see what a change in air density (such as taking the extreme
case of a vacuum) has to do with lift. Unless you are claiming
density change as a requirement?

I believe lift can be reasonably computed using inviscid
_incompressible_ flow theory (e.g. as far back as Kutta's 1902
dissertation,) so I don't see why any change in _density_ - much less
the vacuum edge case - needs to be invoked.


Any change in pressure is *by definition* a change in the number of
particles in the fluid that are impacting the surface.


That assertion is incorrect. You are no dummy so I'm sure you'll correct it
when you realize the errors.


Sorry, but it's not. Pressure is created by particle collisions.


I never mentioned density.


Sorry, but you used the word "vacuum." The notable characteristic of a
vacuum is that its density is zero.


That is *a* notable characteristic.

--
Alan Baker
Vancouver, British Columbia
http://gallery.me.com/alangbaker/100008/DSCF0162/web.jpg
  #7  
Old December 3rd 09, 01:07 AM posted to rec.aviation.homebuilt
Brian Whatcott
external usenet poster
 
Posts: 915
Default visualisation of the lift distribution over a wing

Alan Baker wrote:
In article ,
Jim Logajan wrote:


Any change in pressure is *by definition* a change in the number of
particles in the fluid that are impacting the surface.


That assertion is incorrect. You are no dummy so I'm sure you'll correct it
when you realize the errors.


Sorry, but it's not. Pressure is created by particle collisions.


Hmmm...looks like Jim expected too much from you: the kinetic theory of
gases has it that pressure may be computed from the temperature AND the
density of gases... that is to say, by retaining the SAME molar quantity
of gas, and raising its temperature (which translates to a higher
velocity), the pressure is increased P.V = R.t and all that....

Put it another way: each "hotter" molecule reverses direction at a
surface with greater force.

Brian W
  #8  
Old December 3rd 09, 01:14 AM posted to rec.aviation.homebuilt
Alan Baker
external usenet poster
 
Posts: 244
Default visualisation of the lift distribution over a wing

In article ,
brian whatcott wrote:

Alan Baker wrote:
In article ,
Jim Logajan wrote:


Any change in pressure is *by definition* a change in the number of
particles in the fluid that are impacting the surface.


That assertion is incorrect. You are no dummy so I'm sure you'll correct
it
when you realize the errors.


Sorry, but it's not. Pressure is created by particle collisions.


Hmmm...looks like Jim expected too much from you: the kinetic theory of
gases has it that pressure may be computed from the temperature AND the
density of gases... that is to say, by retaining the SAME molar quantity
of gas, and raising its temperature (which translates to a higher
velocity), the pressure is increased P.V = R.t and all that....

Put it another way: each "hotter" molecule reverses direction at a
surface with greater force.

Brian W


I'm perfectly aware of that, but that hardly matters for the scope of
our discussion of the effect of pressure on a wing. The point I'm making
is that all else being equal, more collisions means higher pressure and
fewer means lower pressure, but that pressure is therefore always a
positive value that acts toward the surface to which it is applied.

It is *never* acting away from that surface; i.e. "pulling".

That is the only reason I mentioned a vacuum, because it is a situation
in which there is *by definition* zero absolute pressure.

--
Alan Baker
Vancouver, British Columbia
http://gallery.me.com/alangbaker/100008/DSCF0162/web.jpg
  #9  
Old December 3rd 09, 12:54 PM posted to rec.aviation.homebuilt
Brian Whatcott
external usenet poster
 
Posts: 915
Default visualisation of the lift distribution over a wing

Alan Baker wrote:
/snip/
Any change in pressure is *by definition* a change in the number of
particles in the fluid that are impacting the surface.


That assertion is incorrect. You are no dummy so I'm sure you'll correct
it when you realize the errors.


Sorry, but it's not. Pressure is created by particle collisions.


Hmmm...looks like Jim expected too much from you: the kinetic theory of
gases has it that pressure may be computed from the temperature AND the
density of gases... that is to say, by retaining the SAME molar quantity
of gas, and raising its temperature (which translates to a higher
velocity), the pressure is increased P.V = R.t and all that....

Put it another way: each "hotter" molecule reverses direction at a
surface with greater force.

Brian W


I'm perfectly aware of that...


It took me too long to realise the problem: you have a problem with
saying: "Oh yes, I got it worng."

People who WON'T do that in technical discussions qualify as people who
are just happy to stir up heated debate.

I am going to leave this thread now: wrasslin' with pigs gets the
hands jest too soiled...

Brian W
  #10  
Old December 4th 09, 10:13 PM posted to rec.aviation.homebuilt
Jim Logajan
external usenet poster
 
Posts: 1,958
Default visualisation of the lift distribution over a wing

Alan Baker wrote:
Jim Logajan wrote:
Alan Baker wrote:
Any change in pressure is *by definition* a change in the number of
particles in the fluid that are impacting the surface.


That assertion is incorrect. You are no dummy so I'm sure you'll
correct it when you realize the errors.


Sorry, but it's not. Pressure is created by particle collisions.


Brian Whatcott already addressed one of the errors I had in mind. The other
I had in mind was your incorrect assertion "*by definition*". You should
have asserted "*by derivation*". College level texts on statistical and
thermal physics *derive* the gas laws from statistical mechanics; they do
not present them as true "by definition." (Though that would make for short
textbooks!)
 




Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
Pressure Distribution Charts sisu1a Soaring 0 September 21st 08 05:53 PM
Soundwaves Boost Wing Lift [email protected] Home Built 30 September 5th 05 10:21 PM
747 weight distribution Robin General Aviation 25 June 22nd 05 03:53 AM
Distribution of armor on a B-52 B2431 Military Aviation 12 August 16th 04 09:07 PM
Alternator load distribution in a Baron Viperdoc Owning 7 December 9th 03 10:27 PM


All times are GMT +1. The time now is 03:21 PM.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
Copyright ©2004-2025 AviationBanter.
The comments are property of their posters.