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#1
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Knowns Unlimited 2006 Glider
Dear all,
I am trying to understand the "Known Unlimited 2006" glider sequence from IAC. First of all, what is the figure number 6? Just a loop with a 90 degree exit? Second, how is figure 9 flown? Is it one full roll during the first 90 degree on the 180 degree circle followed by a half roll on the last 90 degree of the turn? Or shall the rolls be divided different on the circle? If there is a better place to ask such questions please let me know.... Best regards /Aero |
#2
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Knowns Unlimited 2006 Glider
In article . com,
"AeroSign" wrote: Dear all, I am trying to understand the "Known Unlimited 2006" glider sequence from IAC. First, download the rulebook. http://members.iac.org/contests/rulebook.html First of all, what is the figure number 6? Just a loop with a 90 degree exit? I believe this is a 7/8 loop with a down 45. Second, how is figure 9 flown? Is it one full roll during the first 90 degree on the 180 degree circle followed by a half roll on the last 90 degree of the turn? Or shall the rolls be divided different on the circle? First 90 degrees of turn inside roll, inverted to inverted, followed by an outside roll to upright during the second 90 degrees of the 180 degree turn. If there is a better place to ask such questions please let me know.... Subscribe to the exploder. Not all ISP's will allow access to it. I have Roadrunner, it will not allow access. |
#3
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Knowns Unlimited 2006 Glider
Hi John,
Thanks for your fast answer! Thanks for the link. I have searched the rulebook but I can't find information on how such figures should be interpered. I also found the CIVA rulebook. I think it is a little more detailed when it comes to descriptions of valid line length etc.... I believe this is a 7/8 loop with a down 45. Ohh ofcourse... that makes more sense. It has nothing to do with heading change, I don't know why I interpered it like that.... First 90 degrees of turn inside roll, inverted to inverted, followed by an outside roll to upright during the second 90 degrees of the 180 degree turn. Okay... just to be sure... the rollrate in the first 90 degree of the turn (the inside inverted to inverted roll) will be twice as fast, as the last (outside) ˝ roll? I mean the figure only needs ˝ a roll to return to upright and that has to be devided on the last 90 degree of the turn right? I thought I had to think of it as a 1˝ roll divided on a 180 degree turn - that would be hard do right. I hope my decriptions are understandable - english is not my native language :-) Subscribe to the exploder. I'll try that... Thanks again! /Aero |
#4
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Knowns Unlimited 2006 Glider
In article ,
"Michael Nyrup" aerosign-remove wrote: Hi John, Thanks for your fast answer! Thanks for the link. I have searched the rulebook but I can't find information on how such figures should be interpered. I also found the CIVA rulebook. I think it is a little more detailed when it comes to descriptions of valid line length etc.... I couldn't remember the name CIVA when I responded. They are the keepers of the Aresti catalog which explains each family of maneuvers. http://www.arestisystem.com/english/catalogue/ First 90 degrees of turn inside roll, inverted to inverted, followed by an outside roll to upright during the second 90 degrees of the 180 degree turn. Okay... just to be sure... the rollrate in the first 90 degree of the turn (the inside inverted to inverted roll) will be twice as fast, as the last (outside) ˝ roll? I mean the figure only needs ˝ a roll to return to upright and that has to be devided on the last 90 degree of the turn right? I thought I had to think of it as a 1˝ roll divided on a 180 degree turn - that would be hard do right. Above is correct I hope my decriptions are understandable - english is not my native language :-) This why we use pictures (drawings). Universal language. |
#5
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Knowns Unlimited 2006 Glider
Hi,
The answer to figure 9 is incorrect. The roll rate needs to be the same throughout. The figure is 1/2 of a 3-roll 360 degree turn. The first full roll is done in 120 degrees of turn, the 1/2 roll is done in 60 degrees of turn. Guenther --------------------------------------------------- Guenther Eichhorn | Smithsonian Astrophysical Observatory, Cambridge, MA CPL,ASMELS,Glider,LBH,IA,CFI | Pitts S-2A: N1GE DC-3 type rating | Flying is the Pitts See: http://gei.aerobatics.ws john smith wrote: In article , "Michael Nyrup" aerosign-remove wrote: Hi John, Thanks for your fast answer! Thanks for the link. I have searched the rulebook but I can't find information on how such figures should be interpered. I also found the CIVA rulebook. I think it is a little more detailed when it comes to descriptions of valid line length etc.... I couldn't remember the name CIVA when I responded. They are the keepers of the Aresti catalog which explains each family of maneuvers. http://www.arestisystem.com/english/catalogue/ First 90 degrees of turn inside roll, inverted to inverted, followed by an outside roll to upright during the second 90 degrees of the 180 degree turn. Okay... just to be sure... the rollrate in the first 90 degree of the turn (the inside inverted to inverted roll) will be twice as fast, as the last (outside) ˝ roll? I mean the figure only needs ˝ a roll to return to upright and that has to be devided on the last 90 degree of the turn right? I thought I had to think of it as a 1˝ roll divided on a 180 degree turn - that would be hard do right. Above is correct I hope my decriptions are understandable - english is not my native language :-) This why we use pictures (drawings). Universal language. -- -- Anti-spam email address in header: To reply, remove the string 'abc' from the username |
#7
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Knowns Unlimited 2006 Glider
Markus and Guenther,
Thanks for the clarification, it helped a lot. Actually with your explanation I see that it is written in the rulebook.... I have an additional question regarding sides. For instance figure 9 in the sequence. I understand that I have to roll right (on the vertical) to get back on track... but which side am I supposed to rotate towards in the stall turn? Best regards Michael Nyrup |
#8
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Knowns Unlimited 2006 Glider
Hi,
You have to roll such that you exit the maneuver in the right direction. Figure 9 can be flown in either direction, it doesn't matter, since in either case you exit in the direction where you came from. In figure 5, if you for instance have the wind from the right (form B), and you are flying towards the judges (as drawn on form B), you need to turn to the right. f you were flying away from the judges, you would have to turn to the left. I remember it by visualizing that I have to turn such that my head points into the box.. That will get me flying into the box after the hammerhead turn. Guenther Michael Nyrup wrote: Markus and Guenther, Thanks for the clarification, it helped a lot. Actually with your explanation I see that it is written in the rulebook.... I have an additional question regarding sides. For instance figure 9 in the sequence. I understand that I have to roll right (on the vertical) to get back on track... but which side am I supposed to rotate towards in the stall turn? Best regards Michael Nyrup -- -- Anti-spam email address in header: To reply, remove the string 'abc' from the username |
#9
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Knowns Unlimited 2006 Glider
Hi Guenther,
I am sorry, I wrote figure 9... I was thinking number 5.... I understand that according to form B I need to turn right on the vertical up. But the Hammerhead-turn afterwards... is that a right or a left foot rotation? Thanks for your time. Michael You have to roll such that you exit the maneuver in the right direction. Figure 9 can be flown in either direction, it doesn't matter, since in either case you exit in the direction where you came from. In figure 5, if you for instance have the wind from the right (form B), and you are flying towards the judges (as drawn on form B), you need to turn to the right. f you were flying away from the judges, you would have to turn to the left. I remember it by visualizing that I have to turn such that my head points into the box.. That will get me flying into the box after the hammerhead turn. Guenther Michael Nyrup wrote: Markus and Guenther, Thanks for the clarification, it helped a lot. Actually with your explanation I see that it is written in the rulebook.... I have an additional question regarding sides. For instance figure 9 in the sequence. I understand that I have to roll right (on the vertical) to get back on track... but which side am I supposed to rotate towards in the stall turn? Best regards Michael Nyrup -- -- Anti-spam email address in header: To reply, remove the string 'abc' from the username |
#10
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Knowns Unlimited 2006 Glider
I am sorry, I wrote figure 9... I was thinking number 5.... I understand
that according to form B I need to turn right on the vertical up. But the Hammerhead-turn afterwards... is that a right or a left foot rotation? Hammerheads can be either direction... pilot's choice. Of course, engine torque/p-factor may have something to do with it most pilots hammering left. :-)) |
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