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#7
September 8th 05, 01:06 AM
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"abripl" wrote in message oups.com... With bullet/plane(s) relative horizontal speed of 820ft/s, the other plane reaches the bullet position in (50x3)/820 = 0.183 sec (pretty slow bullet). In that time the bullet falls a vertical distance of 0.5 x 32 x 0.183 x 0.183 ft = 0.536 ft. If the messer plane bottom was at least 0.537 ft (about 7 inches) below bullet firing vertical position its gona hit the other plane. Ignoring air friction, whether the planes are moving or parked on the ground with same separation it does not matter. It is only the relative velocity of the bullet to the planes that counts. But with backward airstream and downward friction the bullet will fall slower down than in vacuum - so better chance of hitting the plane behind. Is this your night school physics home assignment and you are cheating here? 
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