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#5
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Hi,
The answer to figure 9 is incorrect. The roll rate needs to be the same throughout. The figure is 1/2 of a 3-roll 360 degree turn. The first full roll is done in 120 degrees of turn, the 1/2 roll is done in 60 degrees of turn. Guenther --------------------------------------------------- Guenther Eichhorn | Smithsonian Astrophysical Observatory, Cambridge, MA CPL,ASMELS,Glider,LBH,IA,CFI | Pitts S-2A: N1GE DC-3 type rating | Flying is the Pitts See: http://gei.aerobatics.ws john smith wrote: In article , "Michael Nyrup" aerosign-remove wrote: Hi John, Thanks for your fast answer! Thanks for the link. I have searched the rulebook but I can't find information on how such figures should be interpered. I also found the CIVA rulebook. I think it is a little more detailed when it comes to descriptions of valid line length etc.... I couldn't remember the name CIVA when I responded. They are the keepers of the Aresti catalog which explains each family of maneuvers. http://www.arestisystem.com/english/catalogue/ First 90 degrees of turn inside roll, inverted to inverted, followed by an outside roll to upright during the second 90 degrees of the 180 degree turn. Okay... just to be sure... the rollrate in the first 90 degree of the turn (the inside inverted to inverted roll) will be twice as fast, as the last (outside) ˝ roll? I mean the figure only needs ˝ a roll to return to upright and that has to be devided on the last 90 degree of the turn right? I thought I had to think of it as a 1˝ roll divided on a 180 degree turn - that would be hard do right. Above is correct I hope my decriptions are understandable - english is not my native language :-) This why we use pictures (drawings). Universal language. -- -- Anti-spam email address in header: To reply, remove the string 'abc' from the username |
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