gun discharge in cockpit.

On Mar 29, 12:05 am, Roger wrote:

Some one remarked about this statement and I can't find it now.
However I stand by it as phrased.

Except for concrete and/or brick veneer, the walls of a house consist
of a 3/8 or 1/2 piece of plaster board over studs on either 16" or
larger centers plus insulation. The outside wall is a layer of
insulation you could easily stick your fist through covered by either
wood or vinyl siding. Unless you hit one of the studs, a 9mm which is
noted for it's penetrating abilities can go through a lot of material
like that.

You must have some mighty big heating bills.

Most newer balloon frame houses also have a layer of 1/2" to 3/4" OD
particle board on the exterior walls upon which to hang the siding.

Older houses (1960) used even more dense material.

And the only thing that makes a 9 mm round "penetrating" is a Full
Metal Jacket (FMJ). Use a modern hollow point (such as a Speer Gold
Dot) and I doubt a 9 mm will make it through an interior wall without
losing significant energy.

I think you have fallen prey to anti-gun rantings.

The fact is that the impact of a 9mm bullet --at muzzle velocity -- is
equal to a *one pound* weight dropped from a height of 5.96 feet
(achieving a velocity of 19.6 fps) or a ten pound weight dropped from
a height of 0.72 inches (yes, that's 3/4 of an inch!)

Sorry, but that's not a whole lot of power.

As I said before -- a handgun is what you use to fight your way to
your long gun.


Dan Mc

"Dan" wrote in message
...
On Mar 29, 12:05 am, Roger wrote:


And the only thing that makes a 9 mm round "penetrating" is a Full
Metal Jacket (FMJ). Use a modern hollow point (such as a Speer Gold
Dot) and I doubt a 9 mm will make it through an interior wall without
losing significant energy.

An interior wall? Two layers of sheetrock? You need some hands on
experience.


I think you have fallen prey to anti-gun rantings.

The fact is that the impact of a 9mm bullet --at muzzle velocity -- is
equal to a *one pound* weight dropped from a height of 5.96 feet
(achieving a velocity of 19.6 fps) or a ten pound weight dropped from
a height of 0.72 inches (yes, that's 3/4 of an inch!)

Sorry, but that's not a whole lot of power.

As I said before -- a handgun is what you use to fight your way to
your long gun.

You don't know much about gun fights either, do ya?

On Mar 29, 9:11 am, "Maxwell" luv^2^fly^99@^cox.^net wrote:

You don't know much about gun fights either, do ya?

I haven't read as many Soldier of Fortune articles as you, apparently.

"Dan" wrote in message
...
On Mar 29, 9:11 am, "Maxwell" luv^2^fly^99@^cox.^net wrote:

You don't know much about gun fights either, do ya?

I haven't read as many Soldier of Fortune articles as you, apparently.


No, it's because all your training is military, not civilian or law
enforcement.

On 2008-03-29, Dan wrote:
The fact is that the impact of a 9mm bullet --at muzzle velocity -- is
equal to a *one pound* weight dropped from a height of 5.96 feet
(achieving a velocity of 19.6 fps) or a ten pound weight dropped from
a height of 0.72 inches (yes, that's 3/4 of an inch!)

What size of 1lb weight?

It depends on the density of that 1 lb weight. If that weight was
one micron cubed, it would probably go all the way to the centre of
the earth. But 1lb of duck feathers wouldn't even hurt you at that
velocity.

A 1lb weight travelling at 19.6 fps, or in proper units, a 0.455
kilogram weight travelling at 6 metres per second has twenty times the
kinetic energy of a .45 round (around 8 kilojoules, versus the .45's
kinetic energy of about 0.5 kilojoules).

--
From the sunny Isle of Man.
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